Answer:
B. x = 7; AB = 9, AC = 12
Step-by-step explanation:
12/4 = (x + 2)/(x - 4) (similar triangles theorem)
3 = (x + 2)/(x - 4)
Cross multiply
3(x - 4) = (x + 2)
3x - 12 = x + 2
Collect like terms
3x - x = 12 + 2
2x = 14
x = 14/2
x = 7
✔️AB = x + 2 = 7 + 2
AB = 9
✔️AC = (x + 2) + (x - 4) = (7 + 2) + (7 - 4)
AC = 9 + 3
AC = 12
Answer:
Given that an article suggests
that a Poisson process can be used to represent the occurrence of
structural loads over time. Suppose the mean time between occurrences of
loads is 0.4 year. a). How many loads can be expected to occur during a 4-year period? b). What is the probability that more than 11 loads occur during a
4-year period? c). How long must a time period be so that the probability of no loads
occurring during that period is at most 0.3?Part A:The number of loads that can be expected to occur during a 4-year period is given by:Part B:The expected value of the number of loads to occur during the 4-year period is 10 loads.This means that the mean is 10.The probability of a poisson distribution is given by where: k = 0, 1, 2, . . ., 11 and λ = 10.The probability that more than 11 loads occur during a
4-year period is given by:1 - [P(k = 0) + P(k = 1) + P(k = 2) + . . . + P(k = 11)]= 1 - [0.000045 + 0.000454 + 0.002270 + 0.007567 + 0.018917 + 0.037833 + 0.063055 + 0.090079 + 0.112599 + 0.125110+ 0.125110 + 0.113736]= 1 - 0.571665 = 0.428335 Therefore, the probability that more than eleven loads occur during a 4-year period is 0.4283Part C:The time period that must be so that the probability of no loads occurring during that period is at most 0.3 is obtained from the equation:Therefore, the time period that must be so that the probability of no loads
occurring during that period is at most 0.3 is given by: 3.3 years
Step-by-step explanation:
Step-by-step explanation:
csc x / (cot x + tan x)
Write in terms of sine and cosine.
(1 / sin x) / [(cos x / sin x) + (sin x / cos x)]
Multiply top and bottom by sin x.
1 / [cos x + (sin²x / cos x)]
Multiply top and bottom by cos x.
cos x / (cos²x + sin²x)
Use Pythagorean identity.
cos x / 1
cos x
Terminal digit filing is a filing system that
works by means of the last two numbers on files to consolidate them. While
middle digit filling uses a tripartite number, using the first part of the
number for the second sort, middle part for the initial sort, and the third portion
for the final sort. One way they are similar is that the two evade working with
large numbers and overpowers the difficulties of crowding at the end of the
storage.
Answer:
Step 1 is incorrect because it was mutiplied. Instead, you should divide.
Step-by-step explanation:
