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jonny [76]
3 years ago
15

The decay of radium-226 produces an isotope

Chemistry
1 answer:
Korvikt [17]3 years ago
4 0

Answer:

 ²²⁶₈₈Ra → ²²²₈₆Rn + ⁴₂He  +⁰₀γ

Explanation:

This radioactive decay occurs when the unstable radium-226 atom wants to lose energy by emitting an alpha particle from its nucleus which is an helium nucleus with no electron. The radium (86) is transformed to radon(Rn) where the atomic number of radium (88) is reduced by two units into radon, Rn (86) and mass number reduced by 4 units.

The equation for the transformation is;

 ²²⁶₈₈Ra → ²²²₈₆Rn + ⁴₂He  +⁰₀γ  where

²²⁶₈₈Ra ---------radium-226

²²²₈₆Rn -------radon-222

⁴₂He ----------alpha particle

⁰₀γ ------------energy

Note that ⁴₂He can also be written as : ⁴₂∝

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What is the abbreviation for the element with atomic number 11?
VikaD [51]

Answer:

Sodium (Na) has atomic number 11.

5 0
3 years ago
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Consider the gold isotope 197Au. How many electrons, protons, and neutrons are in a neutral 197Au atom?
tangare [24]

Answer:

The 197Au isotope has 79 protons, 79 electrons and 118 neutrons

Explanation:

Step 1: The isotope = 197Au

Step 2: Calculate neutrons, electrons and protons

197 = Number of protons + number of neutrons

Isotopes always have the same proton number ( is the same as the atomic number). For Gold (Au) is this 79.

The number of electrons is equal to the number of protons in a neutral atom. Since we have 79 protons, there are also 79 electrons.

All isotopes of Au have a different number of neutrons.

The number of neutrons = 197 -79 = 118 neutrons

The 197Au isotope has 79 protons, 79 electrons and 118 neutrons

6 0
3 years ago
Given a solution with a pOH of 13.6, what is the [OH-] of the solution?
Lelechka [254]
10^-13.6 = 2.51x10^-14
8 0
3 years ago
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1.15.7 cm3 of HCl completely neutralised 25 cm3 of LiOH. The HCl was 2 mol/dm3.The equation is :
Whitepunk [10]

Answer:

C₂ = 1.26 mol/dm³

Explanation:

Given data:

Volume of HCl =V₁ =  15.7 cm³

Volume of LiOH = V₂ =  25 cm³

Concentration of HCl =C₁ = 2 mol/dm³

Concentration of LiOH =C₂=  ?

Solution:

Chemical equation:

LiOH + HCl    →     LiCl + H₂O

Formula:

C₁V₁   = C₂V₂

by putting values,

15.7 cm₃× 2 mol/dm³ = C₂× 25 cm³

C₂ = 15.7 cm₃× 2 mol/dm³ / 25 cm³

C₂ = 31.4 cm₃.mol/dm³ / 25 cm³

C₂ = 1.26 mol/dm³

8 0
3 years ago
If 56.8 ml of bacl2 solution is needed to precipitate all the sulfate ion in a 554 mg sample of na2so4 (forming baso4), what is
IrinaVladis [17]
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3 0
3 years ago
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