We have 1.2 kg of rust whithin 5 days.
the rate of reaction in grams per hour:
1.2 kg/5 day * 1000 g/kg * 1 day/24 hours = 10.0 grams/hour
hope this help
Answer:
Is is talking about h20 water?
Explanation:
Answer:
0.019 g.
Explanation:
- Firstly, we need to find the no. of moles of oxygen gas:
- We can use the general law of ideal gas: <em>PV = nRT.
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where, P is the pressure of the gas in atm (P = 1.02 atm).
V is the volume of the gas in L (V = 15.0 L).
n is the no. of moles of the gas in mol (n = ??? mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 28°C + 273 = 301.0 K).
∴ n = PV/RT = (1.02 atm)(15.0 L)/(0.0821 L.atm/mol.K)(301.0 K) = 0.62 mol.
- To find the mass of oxygen gas, we have:
<em>no. of moles = mass/molar mass.</em>
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∴ mass of oxygen = (no. of moles)(molar mass) = (0.62 mol)(32.0 g/mol) = 0.019 g.
Answer:
Poor Science
Explanation:
I took the quiz also just think that doesn't seem like a good, higher level scientist, or popular one, SO THERE YOU GUYS GO!!!
