In a particular experiment, the per cent yield is 79.0%. This means that in this experiment, a 7.90-g sample of fluorine yields is 7g of SF6.
<h3>How is Sulphur hexafluoride formed?</h3>
Sulfur Hexafluoride is a disparity agent formed of an inorganic fluorinated inert gas comprised of six fluoride atoms bound to one sulfur atom, with possible diagnostic activity upon imaging.
Thus, a sample of fluorine yields 7g of SF6.
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I did this to the best of my ability. I have a hard time comprehending things sometimes so I’m so so so sorry if it’s wrong
Answer:
XY₂Z₄
2.35 mol Z
Explanation:
A sample of the compound contains 0.221 mol X, 0.442 mol Y, and 0.884 mol Z. We can find the simplest formula (empirical formula) by <em>dividing all the numbers of moles by the smallest one</em>.
X: 0.221/0.221 = 1
Y: 0.442/0.221 = 2
Z: 0.884/0.221 = 4
The simplest formula is XY₂Z₄.
The molar ratio of X to Z is 1:4. The moles of Z in a sample that contained 0.588 moles of X is:
0.588 mol X × (4 mol Z/1 mol X) = 2.35 mol Z
Answer:
Physical change is a temporary change. A chemical change is a permanent change.
Explanation:
A Physical change affects only physical properties i.e. shape, size, etc. Chemical change both physical and chemical properties of the substance including its composition.
Answer:
2.73 is the equilibrium constant for the dissociation of 
gas at 840 degree Celsius.
Explanation:
Initial
0.600 atm 0
Equilibrium
(0.600 atm - p) 2p
Total pressure at equilibrium = P = 0.984 atm
P= 0.600 atm - p)+2p=0.984 atm
p = 0.384 atm
Partial pressure of the gas , 
= (0.600 atm - 0.384 atm)=0.216 atm
Partial pressure of the 
gas, 
= 2(0.384 atm)=0.768 atm
2.73 is the equilibrium constant for the dissociation of gas at 840 degree Celsius.
