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Fudgin [204]
3 years ago
15

Create a graph of y=2x−6. Construct a graph corresponding to the linear equation y=2x−6.

Chemistry
1 answer:
yan [13]3 years ago
7 0
The graph is a straight line with this characteristics:

slope: the coefficient that accompanies the x variable, so it is 2.

x-axis intercept: find from y = 0 => 2x - 6 = 0 => x = 3

y - axis intercept: find from x = 0 => y = 2(0) - 6 = 6.

With that information you can draw you graph.

Just in case you need more information, you can build a table with several values of x and y:

x        y = 2x - 6

-5      2(-5) - 6 = -16

-4      2(-4) - 6 = -14

-3      2(-3) - 6 = -12

-2      2(-2) - 6 = -10

-1      2(-1) - 6 = -8

0        2(0) - 6 = -6

1        2(1) - 6 = -4

2        -2
 
3         0

4         2

5         4

Now you have plenty information to draw the graph.

6         6
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A binding protein binds to a ligand l with a kd of 400 nm what is the concentration of ligand when y is 0.25
vampirchik [111]

Answer:

The answer is 7600 nm.

Explanation:

As, Y = 0.25 = [ L ÷ (400 + (L)]

0.95 x 400 + 0.25 [ L] = [ L ]

380.25  = [ L ] - 0.95 [ L ]

              = 0.05 [L]

[L] = 380 ÷ 0.05 = 7600nm

6 0
3 years ago
Which one is a true statement about exothermic reactions?
Ugo [173]

the answer is c, more heat is being released.

6 0
3 years ago
What is a atomic bond ​
zalisa [80]
1.Electrons can be transferred from one atom to another.
2.Electrons can be shared between neighbouring atoms.
3.Electrons can be shared with all atoms in a material.
3 0
3 years ago
Read 2 more answers
The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically. The following data was obtained: t/min 0
o-na [289]

Answer:

1) The order of the reaction is of FIRST ORDER

2)   Rate constant k = 5.667 × 10 ⁻⁴

Explanation:

From the given information:

The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically.

liquid-phase reaction 2A - B signifies that the reaction is of FIRST ORDER where the rate of this reaction is directly proportional to the concentration of A.

The following data was obtained:

t/min                    0         10         20          30             40          ∞

conc B/(mol/L)    0       0.089    0.153     0.200       0.230    0.312

For  a first order reaction:

K = \dfrac{1}{t} \ In ( \dfrac{C_{\infty} - C_o}{C_{\infty} - C_t})

where :

K = proportionality  constant or the rate constant for the specific reaction rate

t = time of reaction

C_o = initial concentration at time t

C _{\infty} = final concentration at time t

C_t = concentration at time t

To start with the value of t when t = 10 mins

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 - 0}{0.312 - 0.089})

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 }{0.223})

K_1 =0.03358 \  min^{-1}

K_1 \simeq 0.034 \  min^{-1}

When t = 20

K_2= \dfrac{1}{20} \ In ( \dfrac{0.312 - 0}{0.312 - 0.153})

K_2= 0.05 \times  \ In ( 1.9623)

K_2=0.03371 \ min^{-1}

K_2 \simeq 0.034 \ min^{-1}

When t = 30

K_3= \dfrac{1}{30} \ In ( \dfrac{0.312 - 0}{0.312 - 0.200})

K_3= 0.0333 \times  \ In ( \dfrac{0.312}{0.112})

K_3= 0.0333 \times  \ 1.0245

K_3 = 0.03412 \ min^{-1}

K_3 = 0.034 \ min^{-1}

When t = 40

K_4= \dfrac{1}{40} \ In ( \dfrac{0.312 - 0}{0.312 - 0.230})

K_4=0.025 \times  \ In ( \dfrac{0.312}{0.082})

K_4=0.025 \times  \ In ( 3.8048)

K_4=0.03340 \ min^{-1}

We can see that at the different time rates, the rate constant of k_1, k_2, k_3, and k_4 all have similar constant values

As such :

Rate constant k = 0.034 min⁻¹

Converting it to seconds ; we have :

60 seconds = 1 min

∴

0.034 min⁻¹ =(0.034/60) seconds

= 5.667 × 10 ⁻⁴ seconds

Rate constant k = 5.667 × 10 ⁻⁴

4 0
3 years ago
According to Wookieepedia, Kylo Ren stands 1.89 m tall and his mass is 89 kg. Calculate his earth-weight in lbm. (2 pts) a. b. A
harina [27]

Answer:

a) 6312.12 lbm

b)  D = 11.843 inch

Explanation:

GIVEN DATA:

Height of person = 1.89 m = 74.41 inch

mass of person m = 89 kg = 196.211 lbm

a) person earth weight =mg

where g is acceleration due to gravity = 32.17 ft/sec^2

                                     = 196.211\times 32.17 = 6312.12 lbm

b) waist to height ratio = 0.5

waist\ to\  height\  ratio = \frac{circumference\ of\ the\ waist}{height\ of\ the\ person}

circumference of waist =height\  of\  person \times waist\ to\ height ratio

                                       = 74.41 inch \times 0.5

                                        =37.21 inch

we know that circumference is given as = 2\pi r\ or\  \pi D= 37.21

                                                               D = 11.843 inch

6 0
3 years ago
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