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Semenov [28]
3 years ago
12

Gaseous hydrogen iodide is placed in a closed 1.0 L container at 425°C, where it partially decomposes to hydrogen and iodine in

the reaction below. 2 HI (g) ⇌ H2 (g) + I2 (g). At equilibrium it is found that: PHI = 3.53 x 10−3 atm PH2 = 4.79 x 10−4 atm PI2 = 4.79 x 10−4 atm What is the standard free energy change (ΔG°) for this reaction?
Chemistry
1 answer:
Pie3 years ago
8 0

Answer:

ΔG° = 23192 J/mol

Explanation:

For the reaction:

2 HI (g) ⇌ H₂(g) + I₂(g)

It is possible to find Kp thus:

Kp = P(H₂) P(I₂) / P(HI)²

Replacing:

Kp = 4,79x10⁻⁴ × 4,79x10⁻⁴ / (3,53x10⁻³)²

Kp = 0,0184

<em>As moles of products (2) are the same moles of reactants, Kp = K</em>

It is possible to find ΔG° from K, thus:

ΔG° = -RT ln K

where R is <em>8,314472J/molK</em>, temperature in kelvin is 425 + 273,15 = <em>698,15K </em>and K is <em>0,0184</em>

<em />

Replacing:

ΔG° = -<em>8,314472J/molK </em>× <em>698,15K</em>  ln <em>0,0184</em>

<em>ΔG° = 23192 J/mol</em>

<em />

I hope it helps!

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5. In this lab, you continued to add Reagent D to each solution until it turned blue. The purpose was to remove the oxygen to me
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A solution is turning blue means, it is turning it's behavior to Basic from Acidic. Reagent D must be a Basic component so it is increasing the pH of the solution. As reaction does not depend on the phase of the component, it could be anything i.e., Solid, Liquid or gas.

Hope this helps!
5 0
4 years ago
What kind of bond will form between the atoms?
Karo-lina-s [1.5K]

ionic bond:

Bond formed when an atom donates its electron and other atom receives those electrons.

polar covalent:

Bond formed by equal sharing of electrons between both the atoms and there is an electronegativity difference between the two atoms.

Nonpolar covalent:

Bond formed by equal sharing of electrons between both the atoms and there is no electronegativity difference between the two atoms.

Metallic:

Formed between two metals.

So the bond between :

Phosphorus and chlorine-polar covalent bond as it is formed by equal sharing of electrons between both the atoms and there is an electronegativity difference between the two atoms.

Potassium and oxygen -ionic bond as here potassium donates its electron and oxygen receives those electrons

Fluorine and fluorine -Non polar covalent bond as formed by equal sharing of electrons between both the atoms and there is no electronegativity difference between the two atoms.

Copper and aluminum-metallic bond as Formed between two metals.

Carbon and fluorine -polar covalent bond as it is formed by equal sharing of electrons between both the atoms and there is an electronegativity difference between the two atoms.

Carbon and hydrogen --Non polar covalent bond as formed by equal sharing of electrons between both the atoms and there is no electronegativity difference between the two atoms.

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6 0
4 years ago
What is the molarity of a solution containing 12.0 g of NaOH in 250.0 mL of solution?
riadik2000 [5.3K]

Answer:

1.196 M NaOH

Explanation:

Molarity = moles/Volume (L)

moles NaOH = mass NaOH/MM NaOH = 12/40.01 = 0.299 moles NaOH

Volume solution = 250 mL = 0.250L

M = 0.299/0.250=1.196 M NaOH

3 0
3 years ago
Suppose 12.0 g of carbon (c) reacts with 70.0 g of sulfur (s) to give 76.0 g of the compound carbon disulfide 1 c s 2 2 . In the
Nitella [24]

Answer is: mass of unused sulfur is 5.87 grams.

Balanced chemical reaction: C + 2S → CS₂.

m(C) = 12.0 g; mass of carbon.

m(S) = 70.0 g; mass of sulfur.

n(C) = m(C) ÷ M(C).

n(C) = 12 g ÷ 12 g/mol.

n(C) = 1 mol; amount of substance.

n(S) = m(S) ÷ M(S).

n(S) = 70 g ÷ 32.065 g/mol.

n(S) = 2.183 mol.

From chemical reaction: n(C) : n₁(S) = 1 : 2.

n₁(S) = 1 mol · 2 = 2 mol.

Δn(S) = n(S) - n₁(S).

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Δn(S) = 0.183 mol; amount of unused sulfur.

Δm(S) = 0.183 mol · 32.065 g/mol.

Δm(S) = 5.87 g.

4 0
4 years ago
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