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svp [43]
3 years ago
13

Which task best fits the role of a planning engineer?

Engineering
1 answer:
Nonamiya [84]3 years ago
8 0

Answer:

D

Explanation:

ensuring project end on time through carefully planning and organizing

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Use Lagrange multiplier techniques to find the local extreme values of the given function subject to the stated constraint. If a
Leno4ka [110]

Answer:

Explanation:

Given f(x, y) = 5x + y + 2 and g(x, y) = xy = 1

The step by step calculation and appropriate substitution is clearly shown in the attached file.

5 0
4 years ago
If you find yourself suddenly without headlights, slam on your brakes. A. TRUE B. FALSE
BigorU [14]
Should headlight failure happen suddenly, follow these steps. Don't stop suddenly, particularly if there is traffic near you. If you have no visibility, slow down and, at a very slow speed, move onto the slow shoulder. You should be moving slowly enough to avoid hitting anything.
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3 years ago
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Which claim does president Kennedy make in speech university rice ?
mafiozo [28]

Answer:  The United States must lead the space race to prevent future wars.

Explanation: Hope this helps

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3 years ago
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A distillation column at 101 kPa is used to separate 350 kmol/h of a bubble point mixture of toluene and benzene into an overhea
AURORKA [14]

Answer:

A)

  D = 158.42 kmol/h

  B =  191.578 kmol/h

B) Rmin = 1.3095

Explanation:

<u>a) Determine the distillate and bottoms flow rates ( D and B ) </u>

F = D + B ----- ( 1 )

<em>Given data :</em>

F = 350 kmol/j

Xf = 0.45 mole

yD ( distillate comp ) = 0.97

yB ( bottom comp ) = 0.02

back to equation 1

350(0.45) = 0.97 D + 0.02 B  ----- ( 2 )

where; B = F - D

Equation 2 becomes

350( 0.45 ) = 0.97 D + 0.02 ( 350 - D )  ------ 3

solving equation 3

D = 158.42 kmol/h

resolving equation 2

B = 191.578 kmol/h

<u>B) Determine the minimum reflux ratio Rmin</u>

The minimum reflux ratio occurs when the enriching line meets the q line in the VLE curve

first we calculate the value of the enriching line

Y =( Rm / R + 1 m ) x   +  ( 0.97 / Rm + 1 )

q - line ;  y =  ( 9 / 9-1 ) x -  xf/9-1

therefore ; x = 0.45

Finally Rmin

=  (( 0.97 / (Rm + 1 ))  = 0.42

0.42 ( Rm + 1 ) = 0.97

∴ Rmin = 1.3095

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8 0
3 years ago
A capacitor in an RC circuit with R = 2 Ω and C = 4 F is being charged. The time required for the capacitor voltage to reach 63.
Anastasy [175]

Given Information:

Resistance = R = 2 Ω

Capacitance = C = 4 F

Required Information:

Time constant = τ = ?

Answer:

τ = 8 seconds

Explanation:

one time constant τ is the amount of time taken when the capacitor chargers up to approximately 63 % of its maximum possible voltage.

τ = RC

τ = 2*4

τ = 8 seconds

So that means after 1 τ (8 seconds) the capacitor voltage will reach approximately 63.2 % of its maximum possible voltage.

7 0
3 years ago
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