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vovangra [49]
3 years ago
5

Universal Containers uses the Case object to track service tickets. They have implemented Case teams to allow multiple support r

epresentatives to manage the Cases. Which two "Filter by owner" options would the user see while creating a list view on the Case object? Choose 2 answers
Engineering
1 answer:
inna [77]3 years ago
6 0

Answer:

Universal Containers uses the Case object to track service tickets. They have implemented Case teams to allow multiple support representatives to manage the Cases. Which two "Filter by owner" options would the user see while creating a list view on the Case object?

Choose 2 answers

A. My Case Teams

B. Roles

C. Public Groups

D. Queue

Correct answer is option A and D

A) My case teams &

D) Queue

Explanation:

Since a case team was implemented to allow multiple support representatives manage the case, the two filter by owner options the user will see are; my case teams and queue.

Queue entails choosing a specific case queue to look at for your view. Which in this case the user will see because the case isn't handled by one person.

In my case teams, cases are filtered to look at only cases where you’re on the case team.

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A missile flying at high speed has a stagnation pressure and temperature of 5 atm and 598.59 °R respectively. What is the densit
alexdok [17]

Answer:

5.31\frac{kg}{m^3}

Explanation:

Approximately, we can use the ideal gas law, below we see how we can deduce the density from general gas equation. To do this, remember that the number of moles n is equal to \frac{m}{M}, where m is the mass and M the molar mass of the gas, and the density is \frac{m}{V}.

For air M=28.66*10^{-3}\frac{kg}{mol} and \frac{5}{9}R=K

So, 598.59 R*\frac{5}{9}=332.55K

pV=nRT\\pV=\frac{m}{M}RT\\\frac{m}{V}=\frac{pM}{RT}\\\rho=\frac{pM}{RT}\\\rho=\frac{(5atm)28.66*10^{-3}\frac{kg}{mol}}{(8.20*10^{-5}\frac{m^3*atm}{K*mol})332.55K}=5.31\frac{kg}{m^3}

7 0
3 years ago
Antilaser eyewear should be worn when a laser​ level's output is greater than​ ____
creativ13 [48]

Answer: 5mW

Explanation:

8 0
2 years ago
You are recording a friend's 3-minute song with 24 bits per sample at 96 kHz sampling rate for a 5.1 surround sound system (6 ch
djyliett [7]

Answer:

save space = 1.9626 Gibibits

Explanation:

given data

recording song time = 3 minute = 180 seconds

song per sample =  24 bits per sample

frequency = 96 kHz

surround sound system = 5.1

solution

first we get here required space for 24 bits at  96 kHz that is

required space = 24 × 96 × 10³ × 6 × 180

required space = 2.48832 × 10^{9}  bits

as 1 Gib bit = 2^{30} bits

so required space = 2.48832 × 10^{9}  bits ÷  2^{30} bits

required space = 2.3174 Gibibits   ...............1

and

space required to save record 16 bit at 44.1 kHz

space required = 16 × 44.1 × 10³ × 3 × 180

space required = 0.381024 × 10^{9}  bits

space required = 0.381024 × 10^{9}  bits  ÷  2^{30} bits  

space required = 0.3548 Gibibits    ...........2

so

we get here that save space in 16 bit at 44.1 kHz

save space = 2.3174 Gibibit - 0.3548 Gibibits

save space = 1.9626 Gibibits

8 0
3 years ago
Select the correct answer.
Brilliant_brown [7]
The answer is either b or e search it up and you will know the answer by definition
4 0
3 years ago
Read 2 more answers
A wide-sense stationary process X(t) is the input to a linear system whose impulse response is h(t)=2e^(-7t), t≥0.
zimovet [89]

Answer:

The power spectral density of Y(t) is Syy(w) = \frac{32}{(4+w^2)(16+w^2)}

Explanation:

4 0
3 years ago
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