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2 years ago

Multiply. Write the answer in simplest form. 1 3/10×1/8

Engineering

1 answer:

kicyunya [14]2 years ago

4 0

9514 1404 393

Answer:

13/80

Explanation:

The product is ...

(1 3/10)×(1/8) = (13/10)×(1/8) = (13×1)/(10×8) = 13/80

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Answer:

spetember 7th

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When you first start a car after it has been sitting for more than an hour, it pollutes up to ......times more than when the eng

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4 years ago

Read 2 more answers

The files provided in the code editor to the right contain syntax and/or logic errors. In each case, determine and fix the probl

Yanka [14]

Question Continuation

public class DebugOne3{

public static void main(String args){

System.out.print1n("Over the river");

System.out.pr1ntln("and through the woods");

system.out.println("to Grandmother's house we go");

}

Answer:

Line 2: Invalid Syntax for the main method. The main method takes the form

public static void main (String [] args) { }

public static void main (String args []) { }

Line 3: The syntax to print is wrong.

To print on a new line, make use of System.out.println(".."); not System.out.print1n();

Line 4:

To print on a new line, make use of System.out.println(".."); not System.out.pr1ntln();

Line 5:

The case of "system" is wrong.

The correct case is sentence case, "System.out.println" without the quotes

The correct program goes, this:

public class DebugOne3{

public static void main(String [] args){

System.out.println("Over the river");

System.out.println("and through the woods");

System.out.println("to Grandmother's house we go");

}

Explanation:

3 0

3 years ago

Find an expectation value in the n th state of the harmonic oscillator.Find an expectation value in the n th state of the harmon

s344n2d4d5 [400]

The classical motion for an oscillator that starts from rest at location x₀ is

x(t) = x₀ cos(ωt)

The probability that the particle is at a particular x at a particular time t

is given by ρ(x, t) = δ(x − x(t)), and we can perform the temporal average

to get the spatial density. Our natural time scale for the averaging is a half

cycle, take t = 0 → π/ ω

Thus,

ρ = $\frac{1}{\pi / w} \int\limits^\pi_0 {d(x - x_o cos(wt))} \, dt$

Limit is 0 to π/ω

We perform the change of variables to allow access to the δ, let y = x₀ cos(ωt) so that

ρ(x) = $-\frac{w}{\pi } \int\limits^x_x {\frac{d ( x - y)}{x_ow sin(wt)} } \, dy$

Limit is x₀ to -x₀

$\frac{1}{\pi } \int\limits^x_x {\frac{d (x-y)}{x_o\sqrt{1 - cos^2(wt)} } } \, dy$

Limit is -x₀ to x₀

$= \frac{1}{\pi } \int\limits^x_x {\frac{d(x-y)}{\sqrt{x_o^2 - y^2} } } \, dy\\ \\= \frac{1}{\pi\sqrt{x_o^2 - x^2} }$

This has $\int\limits^x_x {p(x)} \, dx = 1$ as expected. Here the limit is -x₀ to x₀

The expectation value is 0 when the ρ(x) is symmetric, x ρ(x) is asymmetric and the limits of integration are asymmetric.

6 0

4 years ago

is used to change physical objects and 3-D ideas into 2-D drawing that effectively describe the design and features of an object

Karolina [17]

Answer:

2D CAD Software Application

Explanation:

Two Dimensional Computer-Aided Design Software Application is otherwise known as 2D CAD software application such as AutoCAD or MicroStation is used to change physical objects and 3-D ideas into a 2-D drawing that effectively describe the design and features of an object, so the object can be documented and manufactured.

The utilization of a 2D CAD software application saves time and revision to construction drawings can quickly be made without having to redesign the whole drawings from the scratch.

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3 years ago