1,2 I think it’s two tho I’m not sure
Answer:
The answer to question 3 should be C. Summarizing the results.
The answer to question 4 should be D. Comparing data from the experiment to the prediction of the hypothesis.
Explanation:
Good the equation is balanced already
There are 26 electrons in the nickel ion in the compound NiS.
<h3>How many electrons does the nickel ion contain in the compound NiS?</h3>
The number of electrons in a neutral Nickel atom is obtained from the atomic number of Nickel.
The atomic number of Nickel is 28, therefore, the neutral nickel atom has 28 electrons.
In the compound NiS, nickel atom loses two electrons to to form the nickel ion.
Number of electrons left = 28 - 2 = 26
Therefore, there are 26 electrons in the nickel ion in the compound NiS.
In conclusion, nickel atom loses two electrons to form nickel ion in NiS.
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The concentration of AlCl3 solution if 150 ml of the solution contains 550 mg of cl- ion is 0.0344 M
calculation
concentration = moles /volume in liters
volume in liters = 150 /1000= 0.15 L
number of moles calculation
write the equation for dissociation of Al2Cl3
that is AlCl3 ⇔ Al^3+ + 3 Cl ^-
find the moles of Cl^- formed
moles =mass/molar mass
mass in grams= 550/ 1000 =0.55 grams
molar mass of Cl^- =35.5 g/mol
moles is therefore= 0.55/35.5 =0.0155 moles
by use of mole ration betweem AlCl3 to Cl^- which is 1:3 the moles of AlCl3 is =0.0155 x 1/3= 5.167 x10^-3 moles
concentration of AlCl3 is therefore= 5.167 x10^-3/ 0.15 =0.0344 M
