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Cerrena [4.2K]
3 years ago
9

GIVING BRAINLISTED

Chemistry
1 answer:
Mice21 [21]3 years ago
6 0

Answer: one molecule of O2.

Explanation: sweet i just took a guess but I believe that if 3 o2 molecules - 2 h2 molecules I think that its just basic maths and it is C because 3-2 = 1 and its o2 remaining, sorry if I’m wrong.

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What is the ph of a 0.40 m h2se solution that has the stepwise dissociation constants k a1 = 1.3 × 10-4 and k a2 = 1.0 × 10-11?
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First, we can neglect the Ka2 value and use Ka1:

according to this equation and by using the ICE table:

              H2Se ⇄  H+ +HSe-
initial    0.4 M         0       0 
change  -X             +X        +X 
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so,

Ka1 = [H+][HSe-] / [H2Se]

so by substitution:

1.3 x 10^-4 = X*X / (0.4 -X) by solving for X

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∴PH = -㏒[H+]
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