It’s c I believe but I don’t know
Answer:
Tick
1
2
4
6
Explanation:
magnesium is not a good conductor has some free electrons but it is not used that much in the industries because of other better alternatives.
You can tick number 5 as wlee. Good luck
Find the number of mols of CO2
1 mol of CO2 has a mass of
1 C + 2Os = 12 + 2*16 grams = 44 grams
x mol =0.0418 CO2
1/x = 44/0.0418
44x = 0.0418
x = 0.0418 / 44
x = 0.00095 mol
1 mol of CO2 has 6.02 * 10^23 Carbon atoms in it. Note that is the same number of molecules of CO2 present.
0.00095 mols = x
1/0.00095 = 6.02*10^23) / x
x = 6.02*10^23 * 0.00095
x = 5.719 * 10^20 atoms of carbon in 0.0418 grams of CO2
Answer:
In a video game, a flying coconut moves at a constant velocity of 20 meters/second. The coconut hits an obstacle and moves in the opposite direction with a constant velocity of 10 meters/second.
Explanation:
Answer:
1246 mg = 1.246 g.
Explanation:
- The decay of radioactive elements obeys first-order kinetics.
- For a first-order reaction: <em>k = ln2/(t1/2) = 0.693/(t1/2).</em>
Where, k is the rate constant of the reaction.
t1/2 is the half-life time of the reaction (t1/2 = 10.6 minutes).
∴ <em>k = ln2/(t1/2) = 0.693/10.6 = 6.54 x 10⁻² min⁻¹.</em>
<em></em>
- For first-order reaction: <em>kt = lna/(a-x).</em>
where, k is the rate constant of the reaction (k = <em>6.54 x 10⁻² min⁻¹.</em>).
t is the time of the reaction (t = 1.25 hr x 60 = 75.0 min).
a is the initial concentration (original amount) (a = ??? mg).
(a-x) is the remaining concentration (a-x = 9.25 mg).
∴ kt = lna/(a-x)
(<em>6.54 x 10⁻² min⁻¹</em>)(75.0 min) = ln a/(9.25 mg)
4.903 = ln a/(9.25 mg)
Taking e for the both sides:
134.7 = a/(9.25 mg)
∴ a = (134.7)(9.25 mg) = 1246 mg = 1.246 g.
