Answer:
2:a-heterogenous
b-homogenous
c-heterogenous
d-heterogenous with water
3:Filtration is used to separate insoluble particles from a solution
Distillation is used to separate liquids with close but different boiling points e.g water and ethanol
Explanation:
2: homogenous mixtures form a uniform layer meaning that a mixture containing more than one layer is heterogenous
He can conclude that his experiment has very low precision.
<h3>What is Precision ?</h3>
Precision is defined as the degree of refinement with which an operation is performed or a measurement .
Precision is how close the exact answers are together.
As, the answers are increasing in time.
None of the answers are similar to one another.
Hence, He can conclude that his experiment has very low precision.
Learn more about Precision here ;
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Answer:
The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the remaining electron in the 3s. Therefore the sodium electron configuration will be 1s22s22p63s1.
Explanation:
Answer:
Qsp > Ksp, BaCO3 will precipitate
Explanation:
The equation of the reaction is;
Na2CO3 + BaBr2 -------> 2NaBr + BaCO3
Since BaCO3 may form a precipitate we can determine the Qsp of the system.
Number of moles of Na2CO3 = 0.96g/106 g/mol = 9.1 * 10^-3 moles
concentration of NaCO3 = number of moles/volume of solution = 9.1 * 10^-3 moles/10 L = 9.1 * 10^-4 M
Number of moles of BaBr2 = 0.20g/297 g/mol = 6.7 * 10^-4 moles
concentration of BaBr2 = 6.7 * 10^-4 moles/10 L = 6.7 * 10^-5 M
Hence;
[Ba^2+] = 6.7 * 10^-5 M
[CO3^2-] = 9.1 * 10^-4 M
Qsp = [6.7 * 10^-5] [9.1 * 10^-4]
Qsp = 6.1 * 10^-8
But, Ksp for BaCO3 is 5.1*10^-9.
Since Qsp > Ksp, BaCO3 will precipitate
Copper has 29 protons in the nucleus, while Nickel has 28 protons.
