Attempt 1 of 1

See the questions on the sheet

Sergio [31]

Answer:

Question 1. Nonpolar covalent

Question 2. The fluorine atom is able to attract the shared electrons more strongly than a hydrogen atom

Question 3. True

Explanation:

Question 1

First of all, oxygen is a molecular compound, as it consists of non-metal atoms only (oxygen). This means we wouldn't expect to have any ionic bonding in it, as it doesn't contain a metal ion. A molecular compound has covalent bonding.

Whenever a diatomic molecule contains the same two atoms bonded by a bond, we expect to have a non-polar bond. This is due to the fact that the two atoms are identical and have the same values of electronegativity, meaning the difference in their electronegativity values is 0 and we have no net polarity within the bond.

For a bond between two different atoms, the molecule would be polar, as one atom would have a greater electronegativity (electron withdrawing force) compared to the other atom.

Question 2

Based on the principles of polarity, whenever we have a diatomic molecule, it's only non-polar when the two atoms are the same. In case of HF, we have two different atoms: hydrogen and fluorine. Since the two atoms are not identical, the molecule would be polar overall, as fluorine is more electronegative than hydrogen. Simply speaking, it means that fluorine attracts the shared electrons within the H-F bond stronger than hydrogen does. This makes a difference in electronegativity values between H and F non-zero and an overall polar bond.

Question 3

We may recall the Coulombic force equation. It states that the attraction force is directly proportional to the charge and inversely proportional to the square of a distance between the two charges.

A bond formed between two atoms or ions is the closest distance the two species can approach each other. Intermolecular forces, in contrast, are the forces that atoms experience within a distance greater than the bond length. We may conclude that for a greater distance, the Coulombic force is lower and, hence, the strength of intermolecular forces are significantly lower compared to covalent or ionic bonds.

7 0

3 years ago

6. The modern view of the atom has come a long way from that of a solid, indestructible sphere

Fynjy0 [20]

It is a true statement

4 0

3 years ago

The heats of combustion of ethane (C2H6) and butane (C4H10) are 52 kJ/g and 49 kJ/g, respectively. We need to produce 1.000 x 10

LekaFEV [45]

Answer :

(1) The number of grams needed of each fuel $(C_2H_6)\text{ and }(C_4H_{10})$ are 19.23 g and 20.41 g respectively.

(2) The number of moles of each fuel $(C_2H_6)\text{ and }(C_4H_{10})$ are 0.641 moles and 0.352 moles respectively.

(3) The balanced chemical equation for the combustion of the fuels.

$C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O$

$C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O$

(4) The number of moles of $CO_2$ produced by burning each fuel is 1.28 mole and 1.41 mole respectively.

The fuel that emitting least amount of $CO_2$ is $C_2H_6$

Explanation :

Part 1 :

First we have to calculate the number of grams needed of each fuel $(C_2H_6)\text{ and }(C_4H_{10})$ .

As, 52 kJ energy required amount of $C_2H_6$ = 1 g

So, 1000 kJ energy required amount of $C_2H_6$ = $\frac{1000}{52}=19.23g$

and,

As, 49 kJ energy required amount of $C_4H_{10}$ = 1 g

So, 1000 kJ energy required amount of $C_4H_{10}$ = $\frac{1000}{49}=20.41g$

Part 2 :

Now we have to calculate the number of moles of each fuel $(C_2H_6)\text{ and }(C_4H_{10})$ .

Molar mass of $C_2H_6$ = 30 g/mole

Molar mass of $C_4H_{10}$ = 58 g/mole

$\text{ Moles of }C_2H_6=\frac{\text{ Mass of }C_2H_6}{\text{ Molar mass of }C_2H_6}=\frac{19.23g}{30g/mole}=0.641moles$

and,

$\text{ Moles of }C_4H_{10}=\frac{\text{ Mass of }C_4H_{10}}{\text{ Molar mass of }C_4H_{10}}=\frac{20.41g}{58g/mole}=0.352moles$

Part 3 :

Now we have to write down the balanced chemical equation for the combustion of the fuels.

The balanced chemical reaction for combustion of $C_2H_6$ is:

$C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O$

and,

The balanced chemical reaction for combustion of $C_4H_{10}$ is:

$C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O$

Part 4 :

Now we have to calculate the number of moles of $CO_2$ produced by burning each fuel to produce 1000 kJ.

$C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O$

From this we conclude that,

As, 1 mole of $C_2H_6$ react to produce 2 moles of $CO_2$

As, 0.641 mole of $C_2H_6$ react to produce $0.641\times 2=1.28$ moles of $CO_2$

and,

$C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O$

From this we conclude that,

As, 1 mole of $C_4H_{10}$ react to produce 4 moles of $CO_2$

As, 0.352 mole of $C_4H_{10}$ react to produce $0.352\times 4=1.41$ moles of $CO_2$

So, the fuel that emitting least amount of $CO_2$ is $C_2H_6$

5 0

3 years ago

After a covalent bond has stabilized an atom, the atom will have

padilas [110]

A full valence electron shell.

6 0

3 years ago

Read 2 more answers

What coefficient would the O 2 have after balancing C 4 H 10 +O 2 CO 2 +H 2 O ?

nydimaria [60]

Answer: 6

Explanation:

6 0

3 years ago