PE = mgh
so (75kg)(9.8m/s2)(100m) = 73,500 Joules
KE = 1/2 m * v^2
so (1/2)(75kg)(60m/s)^2 = 135,000 Joules
ME = 208,500 Joules
Answer:
The magnitude of the force exerted by the locomotive on the caboose is 3.08 N.
Explanation:
Given that,
Mass of a toy, m = 2.3 kg
Mass of caboose, m' = 1 kg
The frictional force of the track on the caboose is 0.48 N backward along the track.
The acceleration of train,
The magnitude of the force exerted by the locomotive on the caboose is given by :
So, the magnitude of the force exerted by the locomotive on the caboose is 3.08 N.
Answer:
0.000230144 N
Explanation:
n = Number of electrons =
q = Charge of electron =
k = Coulomb constant =
r = Distance between obects = 1 m
The force would be
The force would be 0.000230144 N
Answer:
The value is
Explanation:
From the question we are told that
The length of the guitar string considered is
The mass is
Generally the tension is mathematically represented as
Here f is the frequency of the note which is
So
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