Question

A 2.3-kg toy locomotive is pulling a 1.0-kg caboose. The frictional force of the track on the caboose is 0.48 N backward along the track. If the train is accelerating forward is 2.6 m/s2, what is the magnitude of the force exerted by the locomotive on the caboose

Answer 1

Answer:

Force applied will be equal to 3.4 N

Explanation:

We have given mass of the toy  is pulling 1 kg caboose

So m = 1 kg

Frictional force f = 0.48 N

Acceleration $a=2.6m/sec^2$

Let the force exerted is F

So $F-F=ma$, here F is force applied f is frictional force m is mass and a is acceleration

So F = f+ ma

$=0.8+1\times 2.6=3.4N$

So force applied will be equal to 3.4 N

Answer 2

Answer:

The magnitude of the force exerted by the locomotive on the caboose is 3.08 N.

Explanation:

Given that,

Mass of a toy, m = 2.3 kg

Mass of caboose, m' = 1 kg

The frictional force of the track on the caboose is 0.48 N backward along the track.

The acceleration of train, $a=2.6\ m/s^2$

The magnitude of the force exerted by the locomotive on the caboose is given by :

$F=m'a+f\\\\F=1\times 2.6+0.48\\\\F=3.08\ N$

So, the magnitude of the force exerted by the locomotive on the caboose is 3.08 N.