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Sunny_sXe [5.5K]

3 years ago

10

A basketball star exerts a force of 3225 n (average value) upon the gym floor in order to accelerate his 76.5-kg body upward. de

termine the acceleration of the player and speed if force continues for 0.150

1 answer:

ryzh [129]3 years ago

8 0

F = m . g = 76.5 x 9..8 = 749.7
Net Force = 3225 - 749.7 = 2475.3

F = m.a
2475.3 = 76.5 a

a = 32.35

V = at + v1
V = at + 0
V = 32.35 x 0.15
V = 4.8525

Hope this helps

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