If a reaction is second-order with respect to a particular reactant, when the concentration of that reactant is increased by a factor of 4, the reaction rate will increased by factor 16.
<h3>How do we calculate the rate of second order reaction?</h3>
Rate of the second order reaction will depends on the concentrations of one second-order reactant or two first-order reactants as:
Rate(1) = k[A]²
If the concentration of reactant becomes 4 times the initial concentration then rate will be:
Rate = k[4A]²
Rate(2) = 16k[A]²
Rate(2) = 16Rate(1)
Hence rate will increased by 16 times.
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Answer:

Explanation:
Hello,
In this case, given the mathematical definition of molar concentration as the moles of solute divided by the liters of solution:

We can easily compute it by firstly computing the moles of sugar by using its molar mass:

After that, we compute the concentration by realizing 259.8 mL equals 0.2598 L:

Or just:

Considering molar units as mol/L
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Answer:
(c.) as the force of Earth's gravity on an object increases, the object's mass increases
Explanation:
Based on newton's law of gravitation "every particle of matter in the universe attracts every other particle with a force that is directly proportional to the product of the masses of the particles and inversely proportional to the square of the distance between them".
It is mathematically expressed as:
F = 
F is the gravitational force on either particle
m₁ and m₂ are the masses
r is the distance between particles
G is the universal gravitation constant.
From this expression, we see that the force of earth's gravity is directly proportional to mass.
Answer:
first number is the correct answer