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Alika [10]
3 years ago
15

Imagine you are holding an apple. Does this apple have energy?how do you know?

Physics
2 answers:
patriot [66]3 years ago
8 0

The apple in my hand has three different forms of energy
that I can think of.

1). Thermal energy.  I know that the apple's temperature is
not absolute zero, because it is not freezing my hand off. 
Therefore it holds some heat energy.

2).  Chemical energy.  From previous experience, I know that
if I eat the apple, it gives me a boost and keeps the doctor away,
since my  body is able to metabolize it, and extract nutrition from
its chemical energy.

3).  Potential energy.  Also from previous experience, I realize
that when I picked up the apple, I exerted force on it opposite to
the force of gravity.  By doing work on it, I endowed it with increased
gravitational potential energy, which would immediately be obvious
if I dropped it to the ground, where it would either smash or dig a
little crater in the grass.
Helga [31]3 years ago
5 0
Yes, the apple has energy.

The apple has energy as a result of it position above the earth surface, it is called potential energy.

You know this by releasing the apple from your hand and you see the apple start falling to the earth.

The potential energy is converted to kinetic energy.
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You are riding in an elevator that is accelerating upward. Suppose you stand on a scale. The reading on the scale is __________.
Darina [25.2K]

Answer: A

Explanation: Your body gets pulled down, causing ur body to have more weight but not mass.

5 0
3 years ago
Read 2 more answers
A test charge of +4 µC is placed halfway between a charge of +6 µC and another of +2 µC separated by 20 cm. (a) What is the magn
S_A_V [24]

Answer:

(a) Magnitude: 14.4 N

(b) Away from the +6 µC charge

Explanation:

As the test charge has the same sign, the force that the other charges exert on it will be a repulsive force. The magnitude of each of the forces will be:

F_e = K\frac{qq_{test}}{r^2}

K is the Coulomb constant equal to 9*10^9 N*m^2/C^2, q and qtest is the charge of the particles, and r is the distance between the particles.

Let's say that a force that goes toward the +6 µC charge is positive, then:

F_e_1 = K\frac{q_1q_{test}}{r^2}=-9*10^9 \frac{Nm^2}{C^2} \frac{6*10^{-6}C*4*10^{-6}C}{(0.1m)^2} =-21.6 N

F_e_2 = K\frac{q_2q_{test}}{r^2}=9*10^9 \frac{Nm^2}{C^2} \frac{2*10^{-6}C*4*10^{-6}C}{(0.1m)^2} =7.2 N

The magnitude will be:

F_e = -21.6 + 7.2 = -14.4 N, away from the +6 µC charge

3 0
3 years ago
How many seconds will elapse between seeing lightning and hearing the thunder if the lightning strikes 1mi (5280 ft) away and th
alexandr1967 [171]

Answer:

t = 4.58 s

Explanation:

In this problem, we need to find the time elapse between seeing lightning and hearing the thunder if the lightning strikes 1mi (5280 ft) away and the air temperature is 90.0°F.

T = 90.0°F = 32.2 °C

The speed of sound at temperature T is given by :

v = (331.3 +0.6T)

Put T = 32.2°C

So,

v = (331.3 +0.6(32.2))

= 350.62 m/s

We have, distance, d = 1 mile = 1609.34

So,

t=\dfrac{d}{v}\\\\t=4.58\ s

So, the required time is equal to 4.58 seconds.

8 0
3 years ago
A brisk walk has a constant speed of 1.7 m/s. how far could a person walk in 160 seconds?
frutty [35]

I believe the answer is 275 m

6 0
3 years ago
One hundred turns of insulated copper wire are wrapped around an iron core of cross-sectional area 0.100m2. As the magnetic fiel
bagirrra123 [75]

Answer:

The voltage induced in the coil  is 1.25 V.

Explanation:

Given;

number of turns, N = 100 turns

cross sectional area of the copper coil, A = 0.1 m²

initial magnetic field, B₁ = 0.5 T

final magnetic field, B₂ = 1.00 T

duration of change in magnetic field, dt = 4 s

The induced emf in the coil is calculated as;

emf = -N\frac{\delta \phi}{\delta t} \\\\emf = - N (\frac{\delta B}{\delta t}) A\\\\emf = -N (\frac{B_1 -B_2}{\delta t} )A\\\\emf = N(\frac{B_2-B_1}{\delta t} )A\\\\emf = 100(\frac{1-0.5}{4} )0.1\\\\emf = 1.25 \ Volts

Therefore, the voltage induced in the coil  is 1.25 V.

6 0
3 years ago
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