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4vir4ik [10]
4 years ago
6

1. A 46000N helicopter feels a net force of 9200N. What litt force is exerted by the air on the propellers?

Physics
1 answer:
Lina20 [59]4 years ago
4 0

Answer:

Force exerted by the air on the propellers = 46000 - 9200

= 36800 N

Hope this helps!

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A stationary charge is located between the poles of a horseshoe magnet. Is a magnetic force excerted of the charge? why?
vredina [299]

A stationary charge is located between the poles of a horseshoe magnet. The magnetic force exerted by the charge is zero.

<h3>What is charge?</h3>

Charge is the physical property of matter which cause a particle to attract or repel when placed in its field.

A stationary charged particle does not interact with a static magnetic field. A charge placed in a magnetic field experiences a magnetic force. There will be no magnetic force acting on a stationary charge. The charge must be moving in order to have magnetic force on it.

Thus, the magnetic force exerted by the charge is zero.

Learn more about charge.

brainly.com/question/19886264

#SPJ4

7 0
2 years ago
If it takes 600 N to move a box 5 meters, how much work is done on the box?
Arada [10]

Answer:3000joules

Explanation: work=force×distance

Work=600×5

Work=3000joules

6 0
4 years ago
The splitting of an atom is called Blank Space __________.
horsena [70]

Fission is the answer

8 0
3 years ago
A flywheel of mass M is rotating about a vertical axis with angular velocity ω0. A second flywheel of mass M/5 is not rotating a
Contact [7]

Answer:

0.83 ω

Explanation:

mass of flywheel, m = M

initial angular velocity of the flywheel, ω = ωo

mass of another flywheel, m' = M/5

radius of both the flywheels = R

let the final angular velocity of the system is ω'

Moment of inertia of the first flywheel , I = 0.5 MR²

Moment of inertia of the second flywheel, I' = 0.5 x M/5 x R² = 0.1 MR²

use the conservation of angular momentum as no external torque is applied on the system.

I x ω = ( I + I') x ω'

0.5 x MR² x ωo = (0.5 MR² + 0.1 MR²) x ω'

0.5 x MR² x ωo = 0.6 MR² x ω'

ω' = 0.83 ω

Thus, the final angular velocity of the system of flywheels is 0.83 ω.

5 0
4 years ago
Calculate the energy per photon and the energy per mole of photons for radiation of wavelength (a) 200 nm (ultraviolet), (b) 150
VMariaS [17]

Answer: a. E =9.9*EXP(-19)J

1 mole E= 596178J

b. E= 1.32*EXP(-15)J, 1 mole E=795MegaJ

c. E= 1.98*EXP(-23)J

1 mole E = 11.9J

Explanation: The Energy of a photon E, the wavelength are related by

E= h*c/wavelength

h is the Planck's constant 6.6*EXP(-34)J.s

c is speed of light 3*EXP(8)m/s

h*c=1.98*EXP(-25)

Now let's solve

a. E = h*c/wavelength

= h*c/(200*EXP(-9)m

=9.9*EXP(-19)J

1 mole of a photon contian 6.022*EXP(23)photons by advogadro

Now to get the energy of 1 mole of the photon we have

9.9*EXP(-19)*6.023*EXP(23)

=596178J

b. E=h*c/150*EXP(-12)m

=1.32*EXP(-15)J

1 mole will have

1.32*EXP(-15)*6.022*EXP(23)J

=795*EXP(6)J

c. E= h*c/1*EXP(-2)m

=1.98*EXP(-23)J

1 mole of the photon will have

1.98*EXP(-23)J *6.022*EXP(23)

= 11.9J.

You will notice that the longer the wavelength of the photon the lesser the Energy it as.

NOTE: EXP represent 10^

8 0
4 years ago
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