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Nataliya [291]
3 years ago
5

​If 250.0 mL of a 0.96 M solution of acetic acid (C 2H 4O 2) are diluted to 800.0 mL, what will be the approximate molarity of t

he final solution?
Chemistry
1 answer:
adoni [48]3 years ago
7 0

Answer:

0.30M HOAc

Explanation:

Given 250.0ml (0.96M HOAc) => 800ml(??M HOAc)

Use the dilution equation...

(Molarity x Volume)concentrated soln = (Molarity x Volume)dilute soln

(0.96M)(250.0ml) = (Molarity diluted soln)(800ml)

Molarity diluted soln = (0.96M)(250.0ml)/(800ml) = 0.30M HOAc

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Covert from scientific notation<br> 1.3 x 10¹²=
Lady_Fox [76]

Answer:

1,300,000,000,000

Explanation:

1.3 x 10^12

We want to convert this from scientific notation.

Tip: in scientific notation the exponent tells you how many place you move the decimal point over. If the exponent is negative you move the decimal point to the left. Ex. For, 4.1 x 10^-8, we would move the decimal point over 8 times to the left to get .00000041. When the exponent is positive we move over to the right. Ex. For, 7.6 x 10^7 we would move the decimal point over 7 times to the right to get 76,000,000

So to convert 1.3 x 10^12 we simply move over the decimal point over 12 times to the right.

1.3 x 10^12 ------> 1,300,000,000,000

Our answer is 1,300,000,000,000

6 0
2 years ago
Need help ASAP !!
Kitty [74]

Answer:

it's a segment

Explanation:

it has multiple end points

6 0
3 years ago
What are the two categories of chemical sedimentary rock?
AnnyKZ [126]
Calcite and calcite?
4 0
3 years ago
What does the word homogenous mean?
kkurt [141]

Answer:

Homogeneous means composed of parts of different kinds; having widely different elements or components.

Explanation:

3 0
3 years ago
How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f
BaLLatris [955]

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}

A is the resulting amount after t time

Ao is the initial amount = 50 mg

t= Elapsed time

t half is the half-life of the substance = 14.3 days

We replace the know values into the equation to have an exponential decay function for a 50mg sample

A=\text{ 50 }\times2^{\frac{-t}{14.3}}

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}

So, after 84 days the P-32 remaining will be 0.85 mg

4 0
1 year ago
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