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Ganezh [65]
2 years ago
9

A 0.45 Caliber bullet (m = 0.162 kg) leaving the muzzle of a gun at 860

Physics
1 answer:
Charra [1.4K]2 years ago
3 0

Answer:139.32kgm/s

Explanation:

Mass(m)=0.162kg

Velocity(v)=860m/s

Momentum=mass x velocity

Momentum=0.162 x 860

Momentum=139.32kgm/s

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A string that passes over a pulley has a 0.341 kg mass attached to one end and a 0.625 kg mass attached to the other end. The pu
dalvyx [7]

Answer:

The frictional torque is \tau  = 0.2505 \ N \cdot m

Explanation:

From the question we are told that

   The mass attached to one end the string is m_1 =  0.341 \ kg

   The mass attached to the other end of the string is  m_2 =  0.625 \ kg

    The radius of the disk is  r = 9.00 \ cm  = 0.09 \ m

At equilibrium the tension on the string due to the first mass is mathematically represented as

      T_1 =  m_1 *  g

substituting values

      T_1 =  0.341 * 9.8

      T_1 =  3.342 \ N

At equilibrium the tension on the string due to the  mass is mathematically represented as

      T_2 =  m_2 *  g

     T_2 = 0.625 * 9.8

      T_2 = 6.125 \ N

The  frictional torque that must be exerted is mathematically represented as

      \tau  =  (T_2 * r ) - (T_1 * r )

substituting values  

     \tau  =  ( 6.125 * 0.09 ) - (3.342  * 0.09 )

     \tau  = 0.2505 \ N \cdot m

5 0
3 years ago
What is the equivalent resistance between points A and C if R1=1430, R2=1350, R3=1100, R4=1350, and R5=1150.
Marianna [84]

R1 + R4 = 1430 + 1350 = 2780 = R14    series combination of R1 & R4

R2 + R5 = 1350 + 1150 = 2500 = R25

The circuit has been reduced to 3 resistors in parallel

R314 = 2780 * 1100 / (2780 + 1100) = 788  this is the resistance of the parallel combination of R14 and R3

R31425 = 2500 * 788 / (2500 + 788) = 599 which is the equivalent of the circuit  - you can also use the formula for 3 resistors in parallel but this seems simpler

7 0
3 years ago
How was Galileo curious and observant
Otrada [13]
When he didn't get answers to his ?s he would try to find the replies himself though research and study. <span />
4 0
2 years ago
A person is running at 2 m/s and 20 s later is running at 22 m/s. What is
AysviL [449]
I think it’s 1 m/s^2
8 0
3 years ago
A metal wire is bent into a square and carries auniform current throughout it. The net magneticfield at the center of this squar
belka [17]

Answer:

The statement that the net magnetic field at the center of this square is zero is false.

The net magnetic field inside a conductor must be zero - This is a true statement

Explanation:

The net magnetic field at the center of this square is not equal to  zero.

The net magnetic field at the center of this square is given by the equation below:

B = 2√2μ₀I/πₐ

Where a = the side of the loop, and I is the current.

Thus, the statement that the net magnetic field at the center of this square is zero is false.

The net magnetic field inside a conductor must be zero - This is a true statement because the total charge on the conductor must be equal to zero.

3 0
3 years ago
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