What state has the longest coast

Why is carrying for the earth necessary? explain

monitta

Answer: We will survive

Explanation: Caring for the earth is something that we need to do to live or survive on earth because if we don't we may not survive.

Hope this helps! :)

6 0

3 years ago

Read 2 more answers

Two pulleys are fastened together to form an integral unit. At a certain instant, the indicated belt tensions act on the unit an

tresset_1 [31]

Answer:

α = $21.6 rad/s^2$

Explanation:

Applying the equations of motion to determine angular acceleration of the unit,

The sum of moments about O is equal to the product of angular acceleration and moment of inertia

∑Mo = Io*α

Taking the anticlockwise direction as positive moment,

= ( -(1150) + (1400) ) * (0.5 / 2) + ( (475) - (650) ) * (0.3 / 2) - F = Io*α

= 36.5 - (2.5 N.m) = $(m*ko^2)$ *α

NOTE: moment of inertia of the pulleys in this instance = $(m*ko^2)$

Hence, 33.75 = $25 * (0.25)^2$ * α

Solving, α = $21.6 rad/s^2$

8 0

3 years ago

a foul ball is hit into the stands at a baseball game. the ball rises to a height of 38 meters and is caught on its way down by

lisov135 [29]

The velocity of the ball when it was caught is 12.52 m/s.

<em>"Your question is not complete it seems to be missing the following, information"</em>,

find the velocity of the ball when it was caught.

The given parameters;

maximum height above the ground reached by the ball, H = 38 m

height above the ground where the ball was caught, h = 30 m

The height traveled by the ball when it was caught is calculated as follows;

y = H - h

y = 38 - 30 = 8 m

The velocity of the ball when it was caught is calculated as;

$v_f^2 = v_0 + 2gh\\\\v_f^2 = 0 + (2\times 9.8 \times 8)\\\\v_f^2 = 156.8\\\\v_f = \sqrt{156.8} \\\\v_f = 12.52 \ m/s$

Thus, the velocity of the ball when it was caught is 12.52 m/s.

Learn more here: brainly.com/question/14582703

4 0

3 years ago

Compare and contrast the strength of the forces between two objects with a mass of 1 kg each, a charge of 10

DochEvi [55]

Answer:

Let's see the similarities between the two forces

* are proportional to the product of a magnitude, mass or charge

* They are inversely proportional to the square of the distance

* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.

The differences in them

* The electric force in much greater than the gravitational force

* The gravitational force is always attractive, the electrical force can be attractive or repulsive.

Explanation:

Let's start by calculating each force.

Gravitational force

F = $G \frac{m_1m_2}{r^2}$

let's calculate

F = 6.67 10⁻¹¹ 1 1 / 1²

F = 6.67 10⁻¹¹ N

Electric force

F = $k \frac{q_1q_2}{r^2}$

indicates that the charge is q = 10 C

F = 9 10⁹ 10 10 / 1²

F = 9 10¹¹ N

Let's see the similarities between the two forces

* are proportional to the product of a magnitude, mass or charge

* They are inversely proportional to the square of the distance

* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.

The differences in them

* The electric force in much greater than the gravitational force

* The gravitational force is always attractive, the electrical force can be attractive or repulsive.

3 0

3 years ago

A steel ball attached to a spring moves in simple harmonic motion. The amplitude of the ball's motion is 11.0 cm, and the spring

Dmitriy789 [7]

Answer:

a) m = 0.626 kg , b) T = 2.09 s , c) a = 1.0544 m / s²

Explanation:

In a spring mass system the equation of motion is

x = A cos (wt + Ф)

with w = √(k / m)

a) velocity is defined by

v = dx / dt

v = - A w sin (wt + Ф) (1)

give us that the speed is

v = 26.1 m / s

for the point

x = a / 2

the range of motion is a = 11.0 cm

x = 11.0 / 2

x = 5.5 cm

Let's find the time it takes to get to this distance

wt + Ф = cos⁻¹ (x / A)

wt + Ф = cos 0.5

wt + Ф = 0.877

In the exercise they do not indicate that the body started its movement with any speed, therefore we assume that for the maximum elongation the body was released, therefore the phase is zero f

Ф = 0

wt = 0.877

t = 0.877 / w

we substitute in equation 1

26.1 = -11.0 w sin (w 0.877 / w)

w = 26.1 / (11 sin 0.877))

w = 3.096 rad / s

from the angular velocity equation

w² = k / m

m = k / w²

m = 6 / 3,096²

m = 0.626 kg

b) angular velocity and frequency are related

w = 2π f

frequency and period are related

f = 1 / T

we substitute

w = 2π / T

T = 2π / w

T = 2π / 3,096

T = 2.09 s

c) maximum acceleration

the acceleration of defined by

a = dv / dt

a = - Aw² cos (wt)

the acceleration is maximum when the cosine is ±1

a = A w²

a = 11 3,096²

a = 105.44 cm / s²

we reduce to m / s

a = 1.0544 m / s²

5 0

4 years ago