Answer:
La probabilidad pedida es 
Explanation:
Sabemos que la probabilidad de que un nuevo producto tenga éxito es de 0.85. Sabemos también que se eligen 10 personas al azar y se les pregunta si comprarían el nuevo producto. Para responder a la pregunta, primero definiremos la siguiente variable aleatoria :
'' Número de personas que adquirirán el nuevo producto de 10 personas a las que se les preguntó ''
Ahora bien, si suponemos que la probabilidad de que el nuevo producto tenga éxito se mantiene constante
y además suponemos que hay independencia entre cada una de las personas al azar a las que se les preguntó ⇒ Podemos modelar a
como una variable aleatoria Binomial. Esto se escribe :
~
en donde
es el número de personas entrevistadas y
es la probabilidad de éxito (una persona adquiriendo el producto) en cada caso.
Utilizando los datos ⇒
~ 
La función de probabilidad de la variable aleatoria binomial es :
con 
Si reemplazamos los datos de la pregunta en la función de probabilidad obtenemos :
con 
Nos piden la probabilidad de que por lo menos 8 personas adquieran el nuevo producto, esto es :

Calculando
y
por separado y sumando, obtenemos que 
Answer:
1.Plant Grass and Shrubs. Grass and shrubs are very effective at stopping soil erosion. ...
2.Use Erosion Control Blankets to Add 3.Vegetation to Slopes. ...
4.Build Terraces. ...
5.Create Diversions to Help Drainage
Answer:
The length of tank is found to be 0.6 m or 600 mm
Explanation:
In order to determine the length, we need to find a volume for the tank.
For this purpose, we use ideal gas equation:
PV = nRT
n = no. of moles = m/M
Therefore,
PV = (m/M)(RT)
V = (mRT)/(MP)
where,
V = volume of air = volume of container
m = mass of air = 4.64 kg
R = General Gas Constant = 8.314 J/mol.k
T = temperature of air = 10°C + 273 = 283 K
M = molecular mass of air = 0.02897 kg/mol
P = Pressure of Air = 20 MPa = 20 x 10^6 N/m²
V = (4.64 kg)(8.314 J/mol.k)(283 k)/(0.02897 kg/mol)(20 x 10^6 N/m²)
V = 0.01884 m³
Now, the volume of cylindrical tank is given as:
V = 0.01884 m³ = π(Diameter/2)²(Length)
Length = (0.01884 m³)(4)/π(0.2 m)²
<u>Length = 0.6 m = 600 mm</u>
Answer:
See explanation
Explanation:
Solution:-
- The shell and tube heat exchanger are designated by the order of tube and shell passes.
- A single tube pass: The fluid enters from inlet, exchange of heat, the fluid exits.
- A multiple tube pass: The fluid enters from inlet, exchange of heat, U bend of the fluid, exchange of heat, .... ( nth order of pass ), and then exits.
- By increasing the number of passes we have increased the "retention time" of a specific volume of tube fluid; hence, providing sufficient time for the fluid to exchange heat with the shell fluid.
- By making more U-turns we are allowing greater length for the fluid flow to develop with " constriction and turns " into turbulence. This turbulence usually at the final passes allows mixing of fluid and increases the heat transfer coefficient by:
U ∝ v^( 0.8 ) .... ( turbulence )
- The higher the velocity of the fluids the greater the heat transfer coefficient. The increase in the heat transfer coefficient will allow less heat energy carried by either of the fluids to be wasted ; hence, reduced losses.
Thereby, increases the thermal efficiency of the heat exchanger ( higher NTU units ).