Answe whats the question i can help you
Explanation:
Answer:
Explanation:
= Area of section 1 = 
= Velocity of water at section 1 = 100 ft/min
= Specific volume at section 1 = 
= Density of fluid = 
= Area of section 2 = 
Mass flow rate is given by
The mass flow rate through the pipe is
As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1
The speed at section 2 is .
The reason has to do with the amount of work necessary to remove heat from a substance, which increases substantially the colder you try to go. To reach zero kelvins, you would require an infinite amount of work.
Answer:
For uniaxial tension the objective is to minimize cost:
C = mCm= ALrCm where m is mass, A is the cross-section area, r is density, and Cm is cost per unit mass. For strength limited design: F/A ≤sy, and A ≥ F/sy To minimize C = (F/sy) LrCm= (FL)(rCm/sy), minimize the quantity (rCm/sy). Maximize the material index,M =sy/(rCm)
b. The objective is to minimize cost C = mCm= b2LrCm, where A = b2 is the cross-section for strength limited design. It is necessary to eliminate the variable b from the equation.
Now if A= b2
Then b=A/2
Therefore cost C= mCm=A/2.2LrCm
= ALrCm
