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4 years ago

The period of a 261 Hertz sound wave is

Physics

2 answers:

Studentka2010 [4]4 years ago

6 0

Period = 1/frequency.
Because the frequency is 261, 1/261 = the period :)

Pachacha [2.7K]4 years ago

5 0

Herz is a measurement for how many cycles of the wave occur per second, which in this case is 261. the period is the time it takes to complete 1 cycle, so if 261 cycles occur per second, one cycle occurs every 1/261 seconds

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My older brother received a ticket for driving 80 mph this information describes my brothers?

Sauron [17]

Answer: 80mph describe the speed of your brother

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3 years ago

A plane flies 1,995 miles in a southwesterly direction from Baltimore to Phoenix in 5.00 hours . What is the velocity of the pla

disa [49]

displacement of the plane is given as

$d = 1995 miles$

time taken by the plane

$t = 5.00 hours$

now the velocity is given as

$v = \frac{displacement}{time}$

$v = \frac{1995}{5}$

$v = 399 mi/h$

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3 years ago

How long would it take for a rock falling 97.2 m/s to reach the ground from 100 meters

mote1985 [20]

Answer;

velocity(v) = 97.2 m/s ,

distance (S) = 100 m

determine time(t) = ?

We know that,

distance (S) = velocity(v) × time(t)

So, time (t) = distance ÷ velocity

= 100 ÷ 97.2

<em>I hope this will help you.</em>

5 0

4 years ago

A typical laboratory centrifuge rotates at 4000 rpm. Test tubes have to be placed into a centrifuge very carefully because of th

cestrela7 [59]

Answer:

1. $a_{rad}=17545.2\frac{m}{s^{2}}$

2. $a=4429.45 \frac{m}{s^{2}}$

Explanation:

Radial acceleration is:

$a_{rad}=\frac{v^2}{r}$ (1)

With r the radius respects the axis of rotation and v the tangential velocity that is related with angular velocity (ω) by:

$v= \omega r$ (2)

By (2) on (1):

$a_{rad}= \frac{(\omega r)^2}{r}= (\omega )^2r=(418,88\frac{rad}{s})^2(0.1m)$

$a_{rad}=17545.2\frac{m}{s^{2}}$

To find the acceleration of the tube with the fall, we can use the expression:

$\overrightarrow{J}=\overrightarrow{F}_{avg}(\varDelta t)$ (3)

Due impulse-momentum theorem:

$\overrightarrow{J}=\overrightarrow{p}_{f}-\overrightarrow{p}_{i}$ (4)

with p the momentum and J the impulse. By (4) on (3):

$\overrightarrow{p}_{f}-\overrightarrow{p}_{i}=\overrightarrow{F}_{avg}(\varDelta t)$

And using Newton's second law (F=ma) and that (P=mv):

$mv_f-mv_i=(ma)(\varDelta t)$ (5)

Final velocity is the velocity just after the encounter with hard floor, and initial momentum us just before that moment so the first one is zero and the second one can be found sing conservation of energy:

$\frac{mv_i}{2}=mgh$

$v_i=\sqrt{2gh}=\sqrt{2(9.81)(1.0)}=4.43\frac{m}{s}$

So (5) is:

$-m(4.43)=(ma)(\varDelta t)$

solving for a:

$a=\frac{4.43}{\varDelta t}=\frac{4.43}{1.0\times10^{-3}}=-4429.45$

It’s negative because is opposed to the tube movement.

5 0

3 years ago

The potential energy between two atoms in a particular molecule has the form U(x) = 2.1 x 8 − 5.2 x4 where the units of x are le

a_sh-v [17]

Answer:

$x\approx 0.948$

Explanation:

The correct formula for the potential energy between two atoms in a particular molecule is:

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Where $x$ is the distance.

According to the definitions of potential energy and work, as well as the Work-Energy Theorem and the Principle of Energy Conservation. The relation between that and related force is:

$F = -\frac{dU}{dx}$