All categories

3 years ago

A car accelerates from rest to 90m/s in 3 seconds. What is the acceleration and how far did it travel?

Physics

1 answer:

Inessa [10]3 years ago

4 0

Answer:

Explanation:

1.)acceleration= final velocity-initial velocity/time

90m/s-0m/s /3seconds

=30m/s^2

2.) distance= speed*time

90m/s*3seconds

=270m

You might be interested in

Thermal conduction mostly involves the motion of

Iteru [2.4K]

Thermal conduction mostly involves the motion of
ELECTRONS

7 0

3 years ago

Does the temperature decrease at the beach

8_murik_8 [283]

Answer:

yes

Explanation:

8 0

3 years ago

What is the difference in light that is refracted compared to light that is reflected? Think in terms of speed of light as well

Ber [7]

Answer:

The refracted light wave is bent at an angle while the reflected light wave is bounced back either at 90° or at angle less than 180°.

The refracted light wave changes its speed when it moves from one medium to another based on the density of the medium.

The reflected light does not change its speed once it contacts another medium. It just bounces back with the same speed.

Explanation:

4 0

3 years ago

Why can astronots open the door at space

Debora [2.8K]

<span>They use a mechanism called airlock.</span>

3 0

3 years ago

A .183 kg ball is moving 18.8 m/s when it runs into a spring of spring constant 86.9 N/m. How much KE does the ball have when it

Lemur [1.5K]

Answer:

The value is $KE_B = 20.59 \ J$

Explanation:

From the question we are told that

The mass of the ball is $m = 183 \ kg$

The initial speed of the ball is $u = 18.8 \ m/s$

The spring constant is $k = 86.9 \ N/m$

The compression distance is $x = 0.520 \ m$

Generally the energy stored in the string is mathematically represented as

$E = \frac{1}{2} * k * x^2$

=> $E = \frac{1}{2} * 86.9 * 0.520 ^2$

=> $E = 11.75 \ J$

Generally the kinetic energy of the ball is mathematically represented as

$KE_b = \frac{1}{2} * m * u^2$

=> $KE_b = \frac{1}{2} * 0.183 * (18.8 )^2$

$KE_b = 32.34 \ J$

Generally the KE the ball have when it has compressed the spring is mathematically represented as

$KE_B = KE_b - E$

=> $KE_B = 32.34 - 11.75$

=> $KE_B = 20.59 \ J$

7 0

3 years ago