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Softa [21]
3 years ago
11

What is Kb for CH3NH2(aq) + H2O(1) CH3NH3(aq) + OH (aq)?

Chemistry
1 answer:
statuscvo [17]3 years ago
8 0

Answer:

Kb for CH₃NH₂ (methylamine) is 4.4 × 10⁻⁴

Hope that helps.

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A student weighs out 3.68 grams of cobalt (II) chloride to do an experiment with. How many moles of is this?
leva [86]

Answer:

0.029mol

Explanation:

from

n=m÷mr

where

n is number of moles

m is mass

mr is molar mass

8 0
2 years ago
What is defined as the number of atoms surrounding an atom in a crystal lattice?
Simora [160]

Answer:

coordination number

Explanation:

Coordination number -

In a crystal lattice , the number of atoms that are surrounded to a particular atom , is referred to as the coordination number of the crystal.

In the field of crystallography and chemistry , it is also called the ligancy.

In coordination chemistry , the number of ligands attached to the central metal atom is also known as the coordination number of the coordination compound.

Hence, from the given statement of the question,

The correct term is coordination number.

4 0
3 years ago
Which of the following has helped preserve resources while cutting the demand for energy?
sweet [91]
A is the correct answer
4 0
3 years ago
Read 2 more answers
If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.
vesna_86 [32]

Answer:

Sr(OH)2

Explanation:

We'll begin by calculating the number of mole of carbonic acid in 150mL of 3.5 M carbonic acid solution. This is illustrated below:

Molarity = 3.5M

Volume = 150mL = 150/1000 = 0.15L

Mole of carbonic acid, H2CO3 =..?

Mole = Molarity x Volume

Mole of carbonic acid, H2CO3 = 3.5 x 0.15 = 0.525 mole.

Next, we shall convert 0.525 mole of carbonic acid, H2CO3 to grams.

Mole of H2CO3 = 0.525 mole

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 =..?

Mass = mole x molar mass

Mass of H2CO3 = 0.525 x 62 = 32.55g

Next, we shall write the balanced equation for the reaction. This is given below:

Sr(OH)2 + H2CO3 → SrCO3 + 2H2O

Next, we shall determine the mass of Sr(OH)2 and H2CO3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Sr(OH)2 = 88 + 2(16 + 1) = 88 + 2(17) = 122g/mol

Mass of Sr(OH)2 from the balanced equation = 1 x 122 = 122g

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 from the balanced equation = 1 x 62 = 62g.

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Finally, we shall determine the limiting reactant as follow:

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Therefore, 12.5g of Sr(OH)2 will react with = (12.5 x 62)/122 = 6.35g.

We can see evidently from the calculations made above that it will take 6.35g out 32.55g of H2CO3 to react with 12.5g of Sr(OH)2. Therefore, Sr(OH)2 is the limiting reactant and H2CO3 is the excess reactant

5 0
3 years ago
Read 2 more answers
86.14 mL of an acid solution was needed to neutralize 30.24 mL of a base solution of unknown concentrations. A second trial is r
Airida [17]

Answer:

The correct answer is option B.

Explanation:

As given ,that 30.24 mL of base was neutralize by 86.14 mL of acid which means that moles of base present in 30.24 mL are neutralized by moles of acid present in 86.14 mL.

After dilution of base from 30.24 mL to 50.0 mL .Since, the moles of base are same in the solution as that of the moles in solution before dilution. Moles of acid require to neutralize the base after dilution will same as a that of present moles of acid present in 86.14 mL.

5 0
3 years ago
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