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3 years ago

What is Kb for CH3NH2(aq) + H2O(1) CH3NH3(aq) + OH (aq)?

Chemistry

1 answer:

statuscvo [17]3 years ago

8 0

Answer:

Kb for CH₃NH₂ (methylamine) is 4.4 × 10⁻⁴

Hope that helps.

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What is the mass, in grams, of one mole of any substance known as?

lbvjy [14]

It is known as its molar mass.

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3 years ago

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Suppose you are performing a gas-producing reaction with an unknown metal, X . X ( s ) + 2 H C l ( a q ) ⟶ X C l 2 ( a q ) + H 2

maksim [4K]

Answer:

600,000,000,000,000,000

Explanation:

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3 years ago

A student is given a 2.002 g sample of unknown acid and is told that it might be butanoic acid, a monoprotic acid (HC4H7O2, equa

Elina [12.6K]

Answer: The identity of the unknown acid is butanoic acid or ascorbic acid.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

Molarity of NaOH solution = 0.570 M

Volume of solution = 39.55 mL

Putting values in above equation, we get:

$0.570M=\frac{\text{Moles of NaOH}\times 1000}{39.55}\\\\\text{Moles of NaOH}=\frac{0.570\times 39.55}{1000}=0.0225mol$

The chemical equation for the reaction of NaOH and monoprotic acid follows:

$NaOH+HX\rightarrow NaX+H_2O$

By Stoichiometry of the reaction:

1 mole of NaOH reacts with 1 mole of HX

So, moles of monoprotic acid = 0.0225 moles

The chemical equation for the reaction of NaOH and diprotic acid follows:

$2NaOH+H_2X\rightarrow 2NaX+2H_2O$

By Stoichiometry of the reaction:

2 moles of NaOH reacts with 1 mole of diprotic acid

So, moles of diprotic acid = $\frac{0.0225}{2}=0.01125moles$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

For butanoic acid:

Mass of butanoic acid = 2.002 g

Molar mass of butanoic acid = 88 g/mol

Putting values in above equation, we get:

$\text{Moles of butanoic acid}=\frac{2.002g}{88g/mol}=0.02275mol$

For L-tartaric acid:

Mass of L-tartaric acid = 2.002 g

Molar mass of L-tartaric acid = 150 g/mol

Putting values in above equation, we get:

$\text{Moles of L-tartaric acid}=\frac{2.002g}{150g/mol}=0.0133mol$

For ascorbic acid:

Mass of ascorbic acid = 2.002 g

Molar mass of ascorbic acid = 176 g/mol

Putting values in above equation, we get:

$\text{Moles of ascorbic acid}=\frac{2.002g}{176g/mol}=0.01137mol$

As, the number of moles of butanoic acid and ascorbic acid is equal to the number of moles of acid getting neutralized.

Hence, the identity of the unknown acid is butanoic acid or ascorbic acid.

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3 years ago

How would the electron configuration of nitrogen change to make a stable configuration?

lesantik [10]

Answer: The electronic configuration of nitrogen is 1s2 2s2 2p3. Thus nitrogen has a half-filled p orbital, which is comparatively more stable. Thus the p orbital is the outermost orbital. To achieve a stable gas configuration, nitrogen needs to have a fulfilled p orbital.

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Draw a resonance structure for the cyclopentadienyl anion. Be sure to show all non-bonding electrons and charges explicitly.

Gennadij [26K]

Answer:

The resonance structure for the cyclopentadienyl anion is shown in the drawing below.

Explanation:

The resonance representation of the cyclopentadienyl anion shows that it is a stable ion. On the other hand it is important to note that it has 6 π electrons and is aromatic.

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3 years ago