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vivado [14]
3 years ago
8

Chemical, gravitational, and elastic are examples of types of what? A. systems B. potential energy C. kinetic energy D. engines

Physics
1 answer:
murzikaleks [220]3 years ago
4 0

Chemical, Gravitational, and Elastic are examples of: B. Potential Energy. Hope it helps.

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Particle accelerators, such as the Large Hadron Collider, use magnetic fields to steer charged particles around a ring Consider
coldgirl [10]

Answer:

\beta= 3.49x10^{-8}T

Explanation:

The magnetic field can be find using the equation

m*v^2/r=q*v*\beta

You can cancel a element of v'

m*v/r=q*\beta

C=36*1m=2\pi*r

r=\frac{36}{2\pi } =5.7295m

Solve to magnetic field

\beta=\frac{m*v^2}{r*q}

The charge and mass of the proton are:

m_p=1.6x10^{27}kg, q_p=1.6x10^{-19}C

Replacing numeric

\beta=\frac{1.6x10^{-27}kg*2x10m/s}{1.6x10^{-19}C*5.73m}

\beta= 3.49x10^{-8}T

6 0
3 years ago
A 600kg car is at rest, and then it accelerates to 5 m/s.
uranmaximum [27]

Answer:

1. 0 J

2. 7500 J

3. 7500 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) of car = 600 Kg

Initial velocity (v₁) of car = 0 m/s

Final velocity (v₂) of car = 5 m/s

Original kinetic energy (KE₁) =?

Final kinetic energy (KE₂) =?

Work used =?

1. Determination of the original kinetic energy.

Mass (m) of car = 600 Kg

Initial velocity (v₁) of car = 0 m/s

Original kinetic energy (KE₁) =?

KE₁ = ½mv₁²

KE₁ = ½ × 600 × 0²

KE₁ = 0 J

Thus, the original kinetic energy of the car is 0 J.

2. Determination of the final kinetic energy.

Mass (m) of car = 600 Kg

Final velocity (v₂) of car = 5 m/s

Final kinetic energy (KE₂) =?

KE₂ = ½mv₂²

KE₂ = ½ × 600 × 5²

KE₂ = 300 × 25

KE₂ = 7500 J

Thus, the final kinetic energy of the car is 7500 J

3. Determination of the work used.

Original kinetic energy (KE₁) = 0

Final kinetic energy (KE₂) = 7500 J

Work used =?

Work used = KE₂ – KE₁

Work used = 7500 – 0

Work used = 7500 J

6 0
2 years ago
Name 3 muscles of the leg​
xxTIMURxx [149]

Answer:

calf

Explanation:

jdjdjddjdjdhdhdj

4 0
3 years ago
In a collision that is not perfectly elastic, what happens to the mechanical energy of the system?
joja [24]
C.

Thanks me later, that's my answer.
5 0
3 years ago
An object moves on a trajectory given by Bold r left parenthesis t right parenthesis equals left angle 10 cosine 6 t comma 10 si
spayn [35]

Answer:

10

Explanation:

(r) = <10 cos 6t, 10 Sin 6t>

The distance traveled by the object is the magnitude of vector r.

The magnitude of vector r is given by

r = \sqrt{(10 Cos 6t)^{2}+(10 Sin 6t)^{2}}

r =10 \sqrt{(Cos^{2} 6t)+(Sin^{2} 6t)

r = 10        

5 0
2 years ago
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