Chemical, gravitational, and elastic are examples of types of what? A. systems B. potential energy C. kinetic energy D. engines

If 3,600 J of work is done in 3.0 s, what is the power?

Firlakuza [10]

Answer:

1,200 watts

Explanation:

1 watt = 1 Joule (J) of work / second

So, 3600 Joules of work / 3 seconds is:

3600 J / 3 seconds = 1,200 watts

8 0

3 years ago

2. What type of motion objects that fall under the pull of gravity?

vivado [14]

Kinetic Energy Pulls Any object to the ground.This Energy is a part of Gravity.
Wish you happy timez!

4 0

3 years ago

A construction crew is paving a road. The crew has already paved 1,000 square feet and can pave at a rate of 300 square feet of

anyanavicka [17]

f(3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount.

Mathematical models are representations of real situations. Models often serve the purpose of prediction and can help to explain and simplify certain mathematical problems.

The model; f(x) = 300x + 1,000 represents the number of additional square feet that can be paved in an hour after 1,000 square feet has already been paved.

From the above we can see that the correct answer is; "900 square feet; f(3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount."

Learn more: brainly.com/question/731147

6 0

2 years ago

Two identical sticky masses m are moving in the xy-plane, with their momenta at an angle of φ with one another. They are each mo

postnew [5]

Answer:

$ucosφ=-v2cosθ2\\\\φ=cos^{-1} (\frac{-v2cosθ2}{cosφ} )$

Explanation:

Two identical sticky masses m are moving in the xy-plane, with their momenta at an angle of φ with one another. They are each moving at the same speed v when they collide at the origin of the coordinates and stick together. After the collision, the masses move at an angle −θ2 with respect to the +x axis at speed v2 .1. What was the angle φ?

from the principle of momentum

In a system of colliding bodies,we know that the total momentum before collision will equal to the total momentum after collision.

Take note that momentum is the product of mass and velocity

momentum before collision=momentum after collision

mass, m

u=initial velocity of the identical masses

v2=the common velocity after the collision

Note that the collision is inelastic , since they both moved with the same velocity

umcosφ+umcosφ=(m+m)v2cos−θ2

2mucosφ=2mv2cos−θ2

$ucosφ=-v2cosθ2\\\\φ=cos^{-1} (\frac{-v2cosθ2}{cosφ} )$

8 0

3 years ago

5) Consider pushing a 50.0 kg box through a 5.00 m displacement on both a flat surface and up a

Svetach [21]

a) The work done by the gravitational force on the flat surface is zero

b) The work done by the gravitational force on the ramp is -634 J

c) The work done by the applied force on the flat surface is 500 J

d) The work done by the applied force on up along the ramp is 500 J

Explanation:

a)

The work done by a force is given by the equation

$W=Fdcos \theta$

where

F is the magnitude of the force

d is the dispalcement of the object

$\theta$ is the angle between the direction of the force and of the displacement

In this problem, we want to calculate the work done by the gravitational force as the box is pushed across the flat ground.

We immediately notice that the gravitational force acts downward, while the displacement is horizontal: therefore, the angle between force and displacement is $90^{\circ}$ ; this means that $cos 90^{\circ}=0$ , and therefore, the work done is zero:

$W=0$

b)

In this case, the box is pushed along the ramp. We have:

$F=mg=(50.0)(9.8)=490 N$ is the magnitude of the force of gravity, where

m = 50.0 kg is the mass of the box

$g=9.8 m/s^2$ is the acceleration of gravity

d = 5.00 m is the displacement of the box along the ramp

The ramp is inclined to the horizontal by $15.0^{\circ}$ , therefore the angle between the force of gravity and the displacement of the box (moving up along the ramp) is: