Answer:
The acceleration that the jet liner that must have is 2.241 meters per square second.
Explanation:
Let suppose that the jet liner accelerates uniformly. From statement we know the initial () and final speeds (), measured in meters per second, of the aircraft and likewise the runway length (), measured in meters. The following kinematic equation is used to calculate the minimum acceleration needed (), measured in meters per square second:
If we know that , and , then the acceleration that the jet must have is:
The acceleration that the jet liner that must have is 2.241 meters per square second.
the wave has a speed of 12 m/s.
Explanation:
Speed is directly proportional to wavelength and frequency. The wave has a frequency of 4 Hz. One Hertz (Hz) is equal to one cycle per second. The image shows that the wave has a wavelength of 3 m. Using the given speed and frequency, the wavelength can be calculated as shown below.
speed= wave length x frequency
speed = 3m x 4Hz
speed = 12m m/6
Answer:
20 meters.
Explanation:
Since it went 100 meters in 10 seconds, that means it is going 10 meters per second. In 2 seconds, it must have gone 20 meters, if the speed is constant.