Answer:
The location of the points is at the distance above the line charge Option A.
Explanation:
Part A
The electric field due to a line of charge is expressed as :
Eₐ = λ
/2πε₀L …… (1)
while the electric field due to a non-conducting elastic sheet is expressed as:
Еₙ = λ
/2ε₀ …… (2)
In order for the particle to experience no force, the electric field at that point is zero.
Equating (1) and (2) together, we have:.
λ
/2πε₀L = σ
/2ε₀
Rearranging the above expression, we have:
L = λ
/πσ
Substituting 50.0 μC/m for λ, 3.14 for π , and 100 μC/
m² for σ, we have:
L= 50.0 μC/m
/ (3.14)* 100 μC/
m²
L = 0.159m
From the L value obtained above, the location of all points where an particle would experience no force due to the arrangement of charged objects is L 0.159m from the line.
Part B
The electric field is zero at all the points above the line with the distance 0.159m from the line.
Thus, the location of the points is at the distance above the line charge Option A.
