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goldenfox [79]
3 years ago
8

Which statements accurately compare the tectonic activity of the planets? Check all that apply.

Physics
2 answers:
Serhud [2]3 years ago
8 0

Answer:The terrestrial planets experience quakes; the gas giants do not.

Terrestrial planets experience (or experienced) tectonic activity; gas giants do (or did) not.

Activity in the molten interior of the terrestrial planets results (or resulted) in tectonic activity.

Explanation: 1,4, & 6

Andreyy893 years ago
4 0

Answer: 1, 4, and 6

Explanation:

took the assignment

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I dont get why its c i dont under the graph for the vertical component in option c
jek_recluse [69]
The vertical component grows at an increasing rate because
gravity is ACCELERATING the object vertically.  So its speed
keeps growing.  Speed is the slope of the displacement graph.
7 0
3 years ago
A jet makes a landing traveling due east with a speed of 120 m/s .
vesna_86 [32]

Average acceleration over a time interval lasting \Delta t is

a_{\rm ave}=\dfrac{\Delta v}{\Delta t}

where \Delta v is the difference in the jet's final and initial velocities. It's coming to a rest, so

a_{\rm ave}=\dfrac{0-120\frac{\rm m}{\rm s}}{13.5\,\rm s}=-8.9\dfrac{\rm m}{\mathrm s^2}

so the average acceleration has magnitude 8.9 m/s^2 and is pointing West (the direction opposite the jet's movement, which should make sense because the jet is slowing down).

7 0
3 years ago
An ion with charge of Q = +3.2 x 10-19 C is in a region where a uniform electric field of magnitude E = 5.0 X 105 V/m is perpend
san4es73 [151]

Answer:

option C

Explanation:

given,

Q = +3.2 x 10⁻¹⁹ C

E = 5.0 X 10⁵ V/m

B = 0.80 T

ion's acceleration is zero  

when acceleration is zero the magnitude of both the forces becomes equal.

q E = q V B

v = \dfrac{E}{B}

v= \dfrac{5 \times 10^5}{0.80}

v = 6.25 × 10⁵ m/s ≈ 6.3 × 10⁵ m/s

hence, the correct answer is option C

8 0
3 years ago
A car accelerates from rest at 1.0 m/s2 for 20.0 second along a straight road. It then moves at a constant speed for half an hou
Whitepunk [10]

Total distance = 36500 m

The average velocity = 19.73 m/s

<h3>Further explanation</h3>

Given

vo=initial velocity=0(from rest)

a=acceleration= 1 m/s²

t₁ = 20 s

t₂ = 0.5 hr = 1800 s

t₃= 30 s

Required

Total distance

Solution

State 1 : acceleration

\tt d=vo.t+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1\times 20^2\rightarrow vo=0\\\\d=200~m

\tt vt=vo+at\\\\vt=at\rightarrow vo=0\\\\vt=1\times 20\\\\vt=20~m/s

State 2 : constant speed

\tt d=v\times t\\\\d=20\times 1800\\\\d=36000~m

State 3 : deceleration

\tt vt=vo+at\rightarrow vt=0(stop)\\\\vo=-at\\\\20=-a.30~s\\\\a=-\dfrac{2}{3}m/s^2(negative=deceleration)

\tt d=vot+\dfrac{1}{2}at^2\\\\d=20.30-\dfrac{1}{2}.\dfrac{2}{3}.30^2\\\\d=300~m

Total distance : state 1+ state 2+state 3

\tt 200 + 36000 + 300=36500~m

the average velocity = total distance : total time

\tt avg~velocity=\dfrac{36500}{20~s+1800~s+30~s}=19.73~m/s

4 0
2 years ago
a ball moves at a constant speed of 1/2 meter per second. How much time does it take the ball to move 1 meter?
lesya [120]

Answer:

2 seconds

Explanation:

if a ball travels 1/2 meter per second, and there's 2 halfs in a whole, 1/2 meter per second x 2 halfs in a whole meter is 2 seconds to travel a meter

4 0
3 years ago
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