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GalinKa [24]
3 years ago
14

A student is taking an animal science and an astronomy class. In animal sciences, she learns that pumas are called mountain lion

s and cougars in different parts of the world, but they are all the same cat. She makes an analogy, or comparison, to something she learned in her astronomy class. She says that a certain space object is like a puma because it is the same object but has different names depending on where it is. What space object is she thinking of?
1. comet
2. meteoroid
3. asteroid
4. meteoride
I know this isn't Physics but they didn't have a Space option
Physics
2 answers:
GarryVolchara [31]3 years ago
8 0

Answer:

2. meteoroid

I saw the question.

user100 [1]3 years ago
8 0

Answer:

2.meteoroid

Explanation:

took test

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While passing a slower car on the highway, you accelerate uniformly from 20.1 m/s to 33.2 m/s in a time of 10.6 s. How far do yo
BaLLatris [955]

Answer:

282 m

Explanation:

Given:

v₀ = 20.1 m/s

v = 33.2 m/s

t = 10.6 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (33.2 m/s + 20.1 m/s) (10.6 s)

Δx ≈ 282 m

5 0
3 years ago
Read 2 more answers
A 80 ohms resistor, 0.2 H inductance and 0.1 mF capacitor are connected in series across a generator (60 Hz, V rms=120 V). Deter
qaws [65]

Answer:

Impedance = 93.75 ohms

Current = 1.81 A

Explanation:

Resistance = R = 80 ohms

Inductance = L = 0.2 H

Inductive reactance = XL = X_{L}= = ωL = (2πf) L

= 2 (3.14) (60)(0.2) = 75.398 Ohms

Capacitive reactance = 1 / ωC = 1/(2πf)C = 1 / [(2π)(60)(0.1 × 10⁻3)]

= 26.526 Ohms  

Impedance = Z = \sqrt{R^{2} + (X_{L} - X_{C})^{^{2}}} =

= \sqrt{8788.511} = 93.747 ohms  

Voltage = \sqrt{2} × 120 = 169.7056 V

Current = I = V ÷ R = (169.7056) ÷ 93,747 = 1.81 A

8 0
3 years ago
Unlike fossil fuels, biomass fuels _____.
dezoksy [38]

the answer is B- are renewable resources

7 0
3 years ago
Read 2 more answers
You shoot an arrow into the air. Two seconds later (2.00 s) the arrow has gone straight upward to a height of 35.0 m above its l
sdas [7]

This question can be solved by using the equations of motion.

a) The initial speed of the arrow is was "9.81 m/s".

b) It took the arrow "1.13 s" to reach a height of 17.5 m.

a)

We will use the second equation of motion to find out the initial speed of the arrow.

h= v_it + \frac{1}{2}gt^2\\

where,

vi = initial speed = ?

h = height = 35 m

t = time interval = 2 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

35\ m = (v_i)(2\ s)+\frac{1}{2}(9.81\ m/s^2)(2\ s)^2\\\\v_i(2\ s)=19.62\ m\\\\v_i = \frac{19.62\ m}{2\ s}

<u>vi =  9.81 m/s</u>

b)

To find the time taken by the arrow to reach 17.5 m, we will use the second equation of motion again.

h= v_it + \frac{1}{2}gt^2\\

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 17.5 m

vi = initial speed = 9.81 m/s

t = time = ?

Therefore,

17.5 = (9.81)t+\frac{1}{2}(9.81)t^2\\4.905t^2+9.81t-17.5=0

solving this quadratic equation using the quadratic formula, we get:

t = -3.13 s (OR) t = 1.13 s

Since time can not have a negative value.

Therefore,

<u>t = 1.13 s</u>

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

4 0
2 years ago
A child in a boat throws a 5.10-kg package out horizontally with a speed of 10.0 m/s. the mass of the child is 27.6 kg and the m
lapo4ka [179]
I am totally lost with this sorry
7 0
3 years ago
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