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GalinKa [24]
3 years ago
14

A student is taking an animal science and an astronomy class. In animal sciences, she learns that pumas are called mountain lion

s and cougars in different parts of the world, but they are all the same cat. She makes an analogy, or comparison, to something she learned in her astronomy class. She says that a certain space object is like a puma because it is the same object but has different names depending on where it is. What space object is she thinking of?
1. comet
2. meteoroid
3. asteroid
4. meteoride
I know this isn't Physics but they didn't have a Space option
Physics
2 answers:
GarryVolchara [31]3 years ago
8 0

Answer:

2. meteoroid

I saw the question.

user100 [1]3 years ago
8 0

Answer:

2.meteoroid

Explanation:

took test

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A student lifts a physical science book off the table and above their head. Is there work being done?
DiKsa [7]

Answer: A force must cause a displacement in order for work to be done. A book falls off a table and free falls to the ground. Yes. This is an example of work.

Explanation:

7 0
2 years ago
A dolphin in an aquatic show jumps straight up out of the water at a velocity of 15.0 m/s. (a) List the knowns in this problem.
astra-53 [7]

Answer:

a)

Y0 = 0 m

Vy0 = 15 m/s

ay = -9.81 m/s^2

b) 7.71 m

c) 3.06 s

Explanation:

The knowns are that the initial vertical speed (at t = 0 s) is 15 m/s upwards. Also at that time the dolphin is coming out of the water, so its initial position is 0 m. And since we can safely assume this happens in Earth, the acceleration is the acceleration of gravity, which is 9.81 m/s^2 pointing downwards

Y(0) = 0 m

Vy(0) = 15 m/s

ay = -9.81 m/s^2 (negative because it points down)

Since acceleration is constant we can use the equation for uniformly accelerated movement:

Y(t) = Y0 + Vy0 * t + 1/2 * a * t^2

To find the highest point we do the first time derivative (this is the speed:

V(t) = Vy0 + a * t

We equate this to zero

0 = Vy0 + a * t

0 = 15 - 9.81 * t

15 = 9.81 * t

t = 0.654 s

At this time it will have a height of:

Y(0.654) = 0 + 15 * 0.654 - 1/2 * 9.81 * 0.654^2 = 7.71 m

The doplhin jumps and falls back into the water, when it falls again it position will be 0 again. So we can equate the position to zero to find how long it was in the air knowing that it started the jump at t = 0s.

0 = Y0 + Vy0 * t + 1/2 * a * t^2

0 = 0 + 15 * t - 1/2 * 9.81 t^2

0 = 15 * t - 4.9 * t^2

0 = t * (15 - 4.9 * t)

t1 = 0 This is the moment it jumped into the air

0 = 15 - 4.9 * t2

15 = 4.9 * t2

t2 = 3.06 s This is the moment when it falls again.

3.06 - 0 = 3.06 s

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2 years ago
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I found this using the app Socratic. When I took physics in high school it helped me so much.

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3 years ago
G a person of mass 100 kg is riding an elevator which was initially moving up with a velocity of 3 m/s. over a distance of 4 m t
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Timed plz hurry
puteri [66]

Answer:

b

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