In order to solve this let us for at assume that the value of the width is X. Therefore the length will be x+5.
We can now write an equation:
(X+5) + (X+5) + X + X = 58
Combining like terms we should get
4X + 10 = 58
Now subtract 10 from both sides to get
4x = 48
Divide by 4 now and you should get
X = 12
Now we know the value of X and therefore the width.
Answer:
(a)
(b) 
Step-by-step explanation:
GIVEN: Suppose that two cards are randomly selected from a standard
card deck.
TO FIND: (a) What is the probability that the first card is a club and the second card is a club if the sampling is done without replacement? (b) What is the probability that the first card is a club and the second card is a club if the sampling is done with replacement.
SOLUTION:
(a)
Probability that first card is club 


As sampling is done without replacement.
probability that second card is club 


Probability that first card is club and second card is club 

(b)
Probability that first card is club 


As sampling is done with replacement.
probability that second card is club 


Probability that first card is club and second card is club 

Given the functions;
f(x) = 5x
g(x) = 2x-1
Required
The composite function f(g(x))
f(g(x)) = f(2x-1)
To get f(2x-1), we are to replace x with 2x-1 in f(x) as shown;
f(2x-1) = 5(2x-1)
Open the parenthesis;
f(2x-1) = 5(2x)-5(1)
f(2x-1) = 10x - 5
f(g(x)) = 10x - 5
Hence the composition f(g(x)) is 10x - 5
It asked for width to length, so it is really important to put the width on top and the length on bottom.
46mm
_____
84mm
Reduce the fraction, if you can use a calculator you do not need to show this part.
46/2
____
84/2