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n200080 [17]
3 years ago
13

a boy is riding a bicycle at a velocity of 5.0 m/s. he applies the brakes and uniformly decelerates to a stop at a rate of 2.5 m

/s. how long does it take for the bicycle to stop.
Physics
1 answer:
JulijaS [17]3 years ago
3 0

The working equation would be Vf (final velocity) = Vi (initial velocity) + a (acceleration) t (time). The given data are the initial velocity (5.0 m/s), acceleration (-2.5 m/s^2, negative since it is said to decelerate) and the final velocity (0 m/s, since it will put to a stop). The time would be 2 seconds. 

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Answer:

v_{avg} = 0

Explanation:

As we know that average velocity is defined as the ratio of total displacement of the object and its time interval.

so here we can say

v_{avg} = \frac{displacement}{time}

now we know that in one complete revolution the total displacement of the tip of the seconds hand is zero

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An object with a charge of 0.9 x 10^-5 C is separated from a second object with a chare of 2.5 x 10^-4 C by a distance of 0.5 m.
meriva

Answer: Force = 81 N

Explanation:

from Columbs law,

F = k(q1*q2)/r²

k = 9 x 10^9 Nm²/C²

F = (9 x 10^9)x (0.9x10^-5 x 2.5x10^-4)/(0.5)²

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A photon with an energy E = 2.12 GeV creates a proton-antiproton pair in which the proton has a kinetic energy of 96.0 MeV. What
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Answer:

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Explanation:

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We know that,

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Put the value into the formula

K.E_{np}=2.12\times10^{9}-2\times938.3\times10^{6}-96\times10^{6}

K.E_{np}=147.4\ MeV

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Explanation:

pa brainliest po :D

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