Every object in the universe attracts every other object with a force which is proportional to the product of their masses and inversely proportional to the square of the distance between them. The forces along the line joining the centre of the two objects.
❍ Let us consider two masses m1 and m2 line at a separation distance d. Let the force of attraction between the two objects be F.
According to universal law of gravitation,
Also,
Combining both, We will get
Or, We can write it as,
Where, G is the constant of proportionality and it is called 'Universal Gravitational constant'.
☯️ Hence, derived !!
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Answer:
2.286 km/s²
Explanation:
Since acceleration a = (v - u)/t where u = initial horizontal velocity of ball = 0 m/s (since it starts from rest), v = final horizontal velocity of ball at serve = 73.14 m/s and t = time taken for serve = 32.0 ms = 0.032 s
Substituting the values of the variables into the equation, we have
a = (v - u)/t
a = (73.14 m/s - 0 m/s)/0.032 s
a = 73.14 m/s/0.032 s
a = 2285.625 m/s²
a = 2.285625 km/s²
a ≅ 2.286 km/s²
So, the x - component of the ball's acceleration during the serve is 2.286 km/s²
Answer:
22
A thermally insulated vessel contains
150 g of water at 0°C. Then the air from the
vessel is pumped out adiabatically. A
fraction of water turns into ice and the rest
evaporates at 0°C itself. The mass of
evaporated water will be closest to:
(Latent heat of vaporization of
water = 2.10 x 106 Jkg - and Latent heat of
Fusion of water = 3.36 x 105J kg-1)
Answer:
The ball will have a kinetic energy of 0.615 Joules.
Explanation:
Use the kinetic energy formula
The kinetic energy at the moment of leaving the hand will be 0.615 Joules. (From there on, as it ball is traveling upwards, this energy will be gradually traded off with potential energy until the ball's velocity becomes zero at the apex of the flight)