Question

A 120 g coconut falls 12 m. What is the kinetic energy of the coconut just before it hits the ground?

Answer 1

Kinetic Energy (Ek) =
$m \times {v}^{2} \div 2$

Torricelli's Equation
g earth = 10m/s^2

${v}^{2} = {vo}^{2} + 2g \times delta(s) \\ {v}^{2} = 0 + 2 \times 10 \times 12 \\ {v}^{2} = 240m/s$

120g = 0.12 kg

Ek = 0.12 x 240/2
Ek = 28.8/2
Ek = 14.4 J