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3 years ago

A 120 g coconut falls 12 m. What is the kinetic energy of the coconut just before it hits the ground?

1 answer:

5 0

Kinetic Energy (Ek) =
$m \times {v}^{2} \div 2$

Torricelli's Equation
g earth = 10m/s^2

${v}^{2} = {vo}^{2} + 2g \times delta(s) \\ {v}^{2} = 0 + 2 \times 10 \times 12 \\ {v}^{2} = 240m/s$

120g = 0.12 kg

Ek = 0.12 x 240/2
Ek = 28.8/2
Ek = 14.4 J

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Explanation:

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The pressure is definited like this:

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Where:

P: Pressure in pascals (Pa)

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Pascal principle

Pm=Ps

Fm/ Am= Fs/ As Formula (1)

Where :

Pm : Pressure on the master piston

Ps : Pressure on the slave piston

Fm : Force on the master piston (N)

Fs: Force on the slave piston ((N)

Am: master piston area (m²)

As: slave piston area (m²)

Area Formula (A)

A= π*R²

R : piston radius

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W = Fs

Data

Fs = 23520 N

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Ds = 24 cm

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Rs = 12 cm

Am = π*Rm² = π*(0.75)²

As = π*Rs² = π*(12)²

Force exerted on the master cylinder

We replace data in the formula (1)

$\frac{F_{m} }{A_{m} } = \frac{F_{s} }{A_{s} }$

$F_{m} = \frac{F_{s}*A_{m} }{A_{s}}$

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$F_{m} = (23520 N)*\frac{(0.75)^{2} }{(12)^{2} }$

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Explanation:

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