It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.
For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).
... x = 1 + t(3-1)
... y = 1 + t(4-1)
ab = {x=1+2t, y=1+3t}
For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).
... x = 3 + t(1-3)
... y = 4 + t(7-4)
bc = {x=3-2t, y=4+3t}
For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).
... x = 1 + t(1-1)
... y = 7 + t(1-7)
ca = {x=1, y=7-6t}
Answer:
16
Step-by-step explanation:
6(3)-2
16
Step-by-step explanation:
let the numbers are:
a, b, and c
the equation would be:
a+b+c = 131
c = 4a
b = a+5
=>
a + a+5 +4a = 131
6a +5 = 131
6a = 131-5
6a = 126
a= 126/6
a = 21
b = a+5 = 21+5
b = 26
c = 4a = 4(21)
c = 84
Answer:
y
=
x
+
1
y
=
−
x
2
+
10
Step-by-step explanation:
I dont know