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aivan3 [116]
3 years ago
15

if a total force exerted by water in a container with a bottom area of 2 square meters is 450 newton's what's the water pressure

at the bottom of the container
Physics
2 answers:
Rina8888 [55]3 years ago
7 0
Pressure =      Force / Area.

Where pressure in in Pascals or N/m²
Force is in Newtons,  Area is in m²

Pressure = 450 N / 2 m²

Pressure = 225 N/m² or 225 Pascals.
Contact [7]3 years ago
6 0

The Correct answer to this question for Penn Foster Students is: 0.225 kPa

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Find the intensity of electromagnetic radiation at the surface of the sun (radius r=R=6.96×105kmr=R=6.96×105km). Ignore any scat
alisha [4.7K]

Answer:

I = 4.46*10^{16}W/m^2.

Explanation:

Intensity I of the electromagnetic radiation is given by

I = \dfrac{P}{4\pi r^2},

where r is the distance from the EM source (the center of the sun, in our case), and P is the power output of the sun and it has the value

P = 3.9 *10^{26}W.

Since the radius of the sun in meters is r = 6.96*10^8km, the intensity I of the electromagnetic radiation at the surface of the sun is

I = \dfrac{3.9*10^{26}W}{4\pi (6.96*10^8m)^2}\\\\\boxed{ I = 4.46*10^{16}W/m^2}

The intensity of the electromagnetic radiation at the surface of the sun is I = 4.46*10^{16}W/m^2.

7 0
3 years ago
Scenario:
katrin [286]

Answer:

h

Explanation:

5 0
2 years ago
Read 2 more answers
2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or
krek1111 [17]

a) The work done by the tree is -1.44\cdot 10^5 J

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

W=Fd

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

W=-1.44\cdot 10^5 J is the work done

d=50.0 cm = 0.50 m is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0
4 years ago
If the force of gravity increases, which measurement will change and how?
alekssr [168]
In physics we refer to how heavy the object is as the mass.

Fg = mass x acceleration due to gravity

Force is directly proportional to mass, thus if force of gravity increases mass also increases.
5 0
3 years ago
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Suppose the line on a distance-versus-time graph and the line on a speed-versus-time graph are both slanted straight lines going
lesya [120]
No, because the distance-time would show a constant velocity but the velocity-time graph shows an increasing velocity.
4 0
4 years ago
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