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Artist 52 [7]
3 years ago
15

What is the distance traveled by an object that moves with an average speed of 6.0 meters per second for 8.0 seconds

Physics
1 answer:
Svetllana [295]3 years ago
4 0

This is a Physics question where we need to figure out how many meters Cam can run per second. To figure this out we divide the distance by the change in time.


40/5.79 = 6.9 meters per second approximately.



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On earth, you swing a simple pendulum in simple harmonic motion with a period of 1.6 seconds. what is the period of this same pe
polet [3.4K]
The period of a simple pendulum is given by
T= 2 \pi  \sqrt{ \frac{L}{g} }
where
L is the pendulum length
g is the acceleration of gravity

If we move the same pendulum from Earth to the Moon, its length L remains the same, while the acceleration of gravity g changes. So we can write the period of the pendulum on Earth as:
T_e= 2 \pi \sqrt{ \frac{L}{g_e} }
where g_e is the acceleration of gravity on Earth, while the period of the pendulum on the Moon is
T_m= 2 \pi \sqrt{ \frac{L}{g_m} }
where g_m is the acceleration of gravity on the Moon. 

If we do the ratio of the two periods, we get
\frac{T_m}{T_e} =  \sqrt{ \frac{g_e}{g_m} }
but the gravity acceleration on the Moon is 1/6 of the gravity acceleration on Earth, so we can write g_e = 6 g_m and we can rewrite the previous ratio as
\frac{T_m}{T_e} = \sqrt{ \frac{6 g_m}{g_m} }=  \sqrt{6}

so the period of the pendulum on the Moon is
T_m =  \sqrt{6}  T_e =  \sqrt{6} (1.6 s)=3.9 s
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In order to have beef becomes tender she will use
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Answer:

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Explanation:

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Forces start and change the motion of an object. Question 1 options: True False
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I think it’s true I may be wrong tho
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3 years ago
an 1800-w toaster, a 1400-w electric frying pan, and a 75-w lamp are plugged into the same outlet in a 15-a, 120-v circuit. (the
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The current drawn by the electric frying pan is <u>27.295 A.</u>

<u />

Power of toaster, P1 = 1800 W

Power of electric frying pan, P2 = 1400 W

Power of lamp, P3 = 75 W

Three devices are in parallel combination. So their Voltage difference is the same.

∆V = 120 Volt

Current is drawn by frying pan, I1 = P1/∆V = 1800/120 = 15 A

Current drawn by an electric frying pan, I2= 1400/120 = 11.67 A

Current drawn by frying pan, I3 = P3/120 = 75/120 = 0.625 A

Total current frying pan= (15 + 11.67 + 0.625) = 27.295 A

Electric current refers to the float of electricity in an electronic circuit, and to the amount of strength flowing via a circuit. it is measured in amperes (A). the bigger the price in amperes, the greater electricity is flowing inside the circuit.

The current is the charge of glide of price across a cross-segment every day to the direction of the float of the current. The S.I. unit of modern is coulomb consistent with 2d which is called ampere and denoted by means of A.

Learn more about current here:-brainly.com/question/24858512

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8 0
2 years ago
The speed of light is about 3.00 × 10 meters per second. What is the frequency of green light that has a wavelength about 500 na
RideAnS [48]

Answer:

The frequency of the green light is 6x10^{14}Hz

Explanation:

The visible region is part of the electromagnetic spectrum, any radiation of that electromagnetic spectrum has a speed of 3.00x10^{8}m/s in the vacuum.

Green light is part of the visible region. Therefore, the frequency can be determined by the following equation:

c = \lambda \cdot \nu  (1)

Where c is the speed of light, \lambda is the wavelength and \nu is the frequency.  

Notice that since it is electromagnetic radiation, equation 1 can be used. Remember that light propagates in the form of an electromagnetic wave (that is a magnetic field perpendicular to an electric field).

Then, \nu can be isolated from equation 1

\nu = \frac{c}{\lambda}  (2)

Notice that it is necessary to express the wavelength in units of meters.  

\lambda = 500nm . \frac{1m}{1x10^{9}nm} ⇒ 5x10^{-7}m

\nu = \frac{3.00x10^{8}m/s}{5x10^{-7}m}

\nu = 6x10^{14}s^{-1}  

\nu = 6x10^{14}Hz  

Hence, the frequency of the green light is 6x10^{14}Hz

4 0
4 years ago
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