Answer:a)1.11×10^-21Nm
b) 1.16×10^-3m
Explanation:see attachment
Answer:
64.2 m/s
Explanation:
We are given that
Speed ,v=38 m/s
We have to find the maximum speed when his car reach on flat ground.
Using dimensional analysis
If 35% acceleration reduced by F(res) at 38 m/s
Then, 100% acceleration can be reduced by F(res) at v' m/s
Substitute the values
Hence, the maximum speed when his car can reach on flat ground=64.2 m/s
Answer:
1. 200 metres West
2. Dividing distance by time
3. Speed was unchanged
4. 1800 metres
5. 15 seconds
Explanation:
Running 500 metres West puts you 500 Metres west from the start. Then running 300 metres east puts you 200metres from where you started.
Since displacement is the distance you are from your original position 200 Metres West is the answer
2. Distance = Speed x Time
Rearrange that to get Speed = Distance / Time
3. Acceleration is when the rate of increase or decrease of speed or the direction is changing. When the speed or sirection dont change acceleration is 0
4. Distance = Speed x Time
60 x 30 = 1800 metres
5. Time = Distance / Speed
300 / 20 = 15 seconds
Answer:
The resultant velocity = 3.16 m/s
Explanation:
Since the boat is moving North of the direction of the riverflow, the river would either be flowing westward or Eastward. The two motions form a right angle triangle with the resultant velocity being the hypotenuse of the traingle.
The resultant velocity will be given as ;
R² = B² + r²
Where B is the velocity of the boat and r is the velocity of the river
R² = 3² + 1²
R² = 10
R = √10 = 3.16 m/s
Therefore, the resultant velocity = 3.16 m/s
Answer: you just know bro
Explanation:
