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klemol [59]
2 years ago
11

Consider the reaction of hydrogen and oxygen producing water. If 26.1 g of water is produced and 23.0 g of oxygen is used, how m

any g of hydrogen are needed?
Chemistry
1 answer:
fredd [130]2 years ago
4 0

Answer:

m_{H_2}=3.1gH_2

Explanation:

Hello,

In this case, given the reaction:

2H_2+O_2\rightarrow 2H_2O

When 23.0 g of oxygen react and 26.1 g of water are yielded, given the law of conservation of mass which states the mass of reactants must equal the mass of products:

m_{H_2}+m_{O_2}=m_{H_2O}

The mass of hydrogen turns out:

m_{H_2}=m_{H_2O}-m_{O_2}\\\\m_{H_2}=26.1g-23.0g\\\\m_{H_2}=3.1gH_2

Best regards.

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