Question

Consider the reaction of hydrogen and oxygen producing water. If 26.1 g of water is produced and 23.0 g of oxygen is used, how many g of hydrogen are needed?

Answer 1

Answer:

$m_{H_2}=3.1gH_2$

Explanation:

Hello,

In this case, given the reaction:

$2H_2+O_2\rightarrow 2H_2O$

When 23.0 g of oxygen react and 26.1 g of water are yielded, given the law of conservation of mass which states the mass of reactants must equal the mass of products:

$m_{H_2}+m_{O_2}=m_{H_2O}$

The mass of hydrogen turns out:

$m_{H_2}=m_{H_2O}-m_{O_2}\\\\m_{H_2}=26.1g-23.0g\\\\m_{H_2}=3.1gH_2$

Best regards.