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Greeley [361]
3 years ago
14

C12H22O11(s) + H2SO4(aq) + 1/2 O2(g) → _C(s) + CO2(g) + 12H2O(g) + SO2(g)

Chemistry
1 answer:
julia-pushkina [17]3 years ago
7 0

Answer:

Law of Conservation of Mass

Explanation:

tells us that matter is neither created nor destroyed during any chemical reaction

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Calculate the molality of an ethylene glycol (C2H6O2) soltuion, that has a molarity of 2.07 M. The density of the solution is 1.
vlada-n [284]

Answer:

2.03

Explanation:

Let's <u>assume we have 1 L of the solution</u>:

  • There would be 2.07 ethylene glycol moles.
  • The solution would weigh (1000 mL * 1.02 g/mL) = 1020 g.

With that information we can <u>calculate the molality</u>:

  • molality = moles of solute / kg of solvent
  • molality = 2.07 moles / (1020 ÷ 1000) = 2.03 m

Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.

3 0
3 years ago
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6 0
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If 2.0 g of water at 0.00°c is to be vaporized, how much heat must be added to it? the specific heat of water is 1.0 cal/g·k, it
krok68 [10]
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6 0
3 years ago
What is the mass ratio of aluminum to oxygen in aluminum oxide, Al2O3?
liubo4ka [24]

Answer:

9 : 8

Explanation:

Aluminum oxide has the following formula Al₂O₃.

Next, we shall determine the mass of Al and O₂ in Al₂O₃. This can be obtained as follow:

Mass of Al in Al₂O₃ = 2 × 27 = 54 g

Mass of O₂ in Al₂O₃ = 3 × 16 = 48 g

Finally, we shall determine the mass ratio of Al and O₂. This can be obtained as follow:

Mass of Al = 54 g

Mass of O₂ = 48 g

Mass of Al : Mass of O₂ = 54 : 48

Mass of Al : Mass of O₂ = 54 / 48

Mass of Al : Mass of O₂ = 9 / 8

Mass of Al : Mass of O₂ = 9 : 8

Therefore, the mass ratio of Al and O₂ in Al₂O₃ is 9 : 8

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3 years ago
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Salsk061 [2.6K]

Answer: A) ionic salt

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3 0
3 years ago
Read 2 more answers
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