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Illusion [34]
3 years ago
10

This involves convection currents.

Physics
2 answers:
Julli [10]3 years ago
6 0
"Wind patterns" is the one among the following choices given in the question that <span>involves convection currents. The correct option among all the options that are given in the question is the second option or option "B". The other choices can be easily negated. i hope that this is the answer that has helped you.</span>
Vitek1552 [10]3 years ago
5 0

Answer:

B

Explanation:

Wind is known as the movement of air molecules from one place to another, and this can also be used as a definition for a convection current.

Convection is the scientific phenomenon where by air molecules become less dense as they get hotter, and as they become less dense, they rise higher into the air. While this happens, colder molecules move into the space where the previous molecule was, and as that one rises, another takes its place. So we are stuck with a continuous loop of moving air molecules. If enough air molecules experience this, such as heating over a large area, affecting a lot of molecules, then wind patterns are created.

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Which of the following is a subsurface event takes place during the rock cycle
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Answer:

The answer is A. Cementing...

Explanation:

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3 years ago
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Radiant heat makes it impossible to stand close to a hot lava flow. Calculate the rate of heat loss by radiation from 1.00 m^2 o
VARVARA [1.3K]

The rate of heat loss by radiation is equal to <u>-207.5kW</u>

Why?

To calculate the heat loss rate (or heat transfer rate) by radiation, from the given situation, we can use the following formula:

HeatLossRate=E*S*A*((T_{cold})^{4} -(T_{hot})^{4} )

Where,

E, is the emissivity of the body.

A, is the area of the body.

T, are the temperatures.

S, is the Stefan-Boltzmann constant, which is equal to:

5.67x10^{-8}\frac{W}{m^{2}*K^{-4} }

Now, before substitute the given information, we must remember that the given formula works with absolute temperatures (Kelvin), so,  we need to convert the given values of temperature from Celsius degrees to Kelvin.

We know that:

K=Celsius+273.15

So, converting we have:

T_{1}=1110\°C+273.15=1383.15K\\\\T_{2}=36.2\°C+273.15=309.35K

Therefore, substituting the given information and calculating, we have:

HeatLossRate=E*S*A*((T_{cold})^{4} -(T_{hot})^{4} )

HeatLossRate=1*5.67x10^{-8}\frac{W}{m^{2}*K^{-4} }*1m^{2} *((309.35K)^{4} -(1383.15})^{4} )\\\\HeatLossRate=5.67x10^{-8}\frac{W}{K^{-4} }*(95697.42K^{4} -3.66x10^{12}K^{4})\\ \\HeatLossRate=5.67x10^{-8}\frac{W}{K^{-4} }*(-3.66x10^{12} K^{4})=-207522W=-207.5kW

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8 0
3 years ago
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Step 3 : Ask for a partner 

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