All categories

3 years ago

Match the element with its description.

Chemistry

2 answers:

dimulka [17.4K]3 years ago

5 0

Explanation:

For 1: Lithium

This element belongs to Group 1 and is considered as a metal. This metal is soft, shiny and shows a property of malleability.

Thus, the correct answer is Malleable, soft and shiny.

For 2: Lead

This element belongs to Group Group 14 and is a solid substance. This element has higher density and is opaque in nature.

Thus, the correct answer is Opaque solid with higher density.

For 3: Fluorine

This element belongs to Group 17 and is a gas. This is highly reactive gas because this element requires only one electron to attain stability and also due to its small size. This is very reactive.

Hence, the correct answer is highly reactive gas.

For 4: Krypton

This element belongs to Group 18 and is considered as a noble gas. Noble gases are the stable gases ans are non-reactive in nature.

Thus, the correct answer is Nonreactive gas.

Lesechka [4]3 years ago

4 0

lithium=Malleable, soft, and shiny

lead= Opaque solid with higher density

fluorine=nonreactive gas

krypton=highly reactive gas.

You might be interested in

Which stament best describes a solution

wel

Where are the following statements ??

3 0

3 years ago

Group 7a of the periodic table contains the most or least reactive elements

Phoenix [80]

I am pretty sure it is the most reactive elements

5 0

3 years ago

Read 2 more answers

When 69.9 g heptane is burned it releases __ mol water.

professor190 [17]

Answer:

1) When 69.9 g heptane is burned it releases 5.6 mol water.

2) C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O.

Explanation:

Firstly, we should balance the equation of heptane combustion.

The balanced equation is: C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O.

This means that every 1.0 mole of complete combustion of heptane will release 8 moles of H₂O.

We need to calculate the no. of moles in 69.9 g of heptane that is burned using the relation: n = mass/molar mass.

n of 69.9 g of heptane = mass/molar mass = (69.9 g)/(100.21 g/mol) = 0.697 mol ≅ 0.7 mol.

Using cross multiplication:

1.0 mol of heptane releases → 8 moles of water.

0.7 mol of heptane releases → ??? moles of water.

∴ The no. of moles of water that will be released from burning (69.9 g) of water = (0.7 mol)(8.0 mol)/(1.0 mol) = 5.6 mol.

∴ When 69.9 g heptane is burned it releases 5.6 mol water.

5 0

3 years ago

When heated, iron (iii) hydroxide

NeX [460]

Fe(OH)3 --> Fe2O3 + H2O

2 Fe(OH)3 --> Fe2O3 + 3H2O

I hope this helps!

8 0

3 years ago

Read 2 more answers

Be sure to answer all parts. A person drinks four glasses of cold water (3.2 degree C) every day. The volume of each glass is 2.

Lelechka [254]

Explanation:

(a). The given data is as follows.

Volume of one glass of water = $2.2 \times 10^{2}$ ml = 220 ml

Volume of 4 glass of water = $220 \times 4$ = 880 ml

We known that density of water is 1 g/ml. Therefore, calculate the mass of water as follows.

Mass of water = $880 ml \times 1 g/ml$

= 880 gm

= 0.88 Kg (as 1 kg = 1000 g)

The relation between heat energy, mass and temperature change is as follows.

Q = $mC \Delta T$

$\Delta T = (37 - 3.2)^{o}C = 33.8^{o}C$

Putting the given values into the above formula as follows.

Q = $mC \Delta T$

= $0.88 \times 4.186 J/g^{o}C \times 33.8^{o}C$

= 124.5 kJ

Hence, the body have to supply 124.5 kJ to raise the temperature of the water to 37 degree C.

(b). As we know that the heat of fusion of ice is 333 J/g.

So, energy required for $8.4 \times 10^{2}$ g or 840 g is as follows.

$333 \times 840$ = 279.72 kJ

Heat capacity of water= 4.184 $J/g^{o}C$

Now, heat energy will be as follows.

Q = $4.184 \times 840 g \times 37^{o}C$

= 130.03 kJ

Therefore, total heat required = (279.72 + 130.03) kJ

= 409.75 kJ

Hence, for the given situation your body should lose 409.75 kJ of heat.

6 0

3 years ago