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Gre4nikov [31]
3 years ago
9

Jsnnsksnabakavw smakanans

Chemistry
2 answers:
Leno4ka [110]3 years ago
8 0

Answer:

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Explanation:

Tresset [83]3 years ago
4 0
Jioutrdxvlokhvvcfyhbvd?
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Pentanitrogen heptachloride formula
Marianna [84]

Answer:

Explanation:

this is the answer hope it helps!(:

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2 years ago
What is the mass of 18.0 mL of honey if its' density is 1.42 g/mL?
BigorU [14]

mass (m) = ? , volume = 18.0 ml , density = 1.42 g/ml .

density =  \frac{mass}{volume}  \\  \\ d =  \frac{m}{v}  \\  \\ mass = density \times volume \\  \\ m = d \times v \\  \\ m = 18 \: ml \times  \: 1.42 \:  \frac{g}{ml}  \\  \\ m = 25.56 \: g

I hope I helped you^_^

8 0
2 years ago
Would you see more living things in a Biome or an Ecosystem?
kicyunya [14]

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A Biome is way bigger than a ecosystem

Explanation:

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2 years ago
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What did alexander fleming discover that earned him the 1945 novel prize of medicine?
Leviafan [203]
He discovered penicillin
6 0
3 years ago
g Consider a uniport system where a carrier protein transports an uncharged substance A across a cell membrane. Suppose that at
Alborosie

Answer :  The ratio of the concentration of substance A inside the cell to the concentration outside is, 296.2

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln Q\\\\\Delta G^o=-RT\times \ln (\frac{[A]_{inside}}{[A]_{outside}})

where,

\Delta G^o = standard Gibbs free energy  = -14.1 kJ/mol

R = gas constant = 8.314 J/K.mol

T = temperature = 25^oC=273+25=298K

Q  = reaction quotient

[A]_{inside} = concentration inside the cell

[A]_{outside} = concentration outside the cell

Now put all the given values in the above formula, we get:

-14.1\times 10^3J/mol =-(8.314J/K.mol)\times (298K)\times \ln (\frac{[A]_{inside}}{[A]_{outside}})

\frac{[A]_{inside}}{[A]_{outside}}=296.2

Thus, the ratio of the concentration of substance A inside the cell to the concentration outside is, 296.2

3 0
2 years ago
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