Answer is: <span>c. 80 g of Br2.
</span>1) n(Li) = 14 g ÷ 7 g/mol
n(Li) = 2 mol.
N(Li) = 2 mol · 6·10²³ 1/mol.
N(Li) = 1,2·10²⁴.
2) n(He) = 4 g ÷ 4 g/mol.
n(He) = 1 mol.
N(He) = 1 mol · 6·10²³ 1/mol.
N(He) = 6·10²³.
3) n(Br₂) = 80 g ÷ 160 g/mol.
n(Br₂) = 0,5 mol.
N(Br₂) = 0,5 mol · 6·10²³ 1/mol.
N(Br₂) = 3·10²³.
4) n(H₂) = 4 g ÷ 2 g/mol = 2 mol.
N(H₂) = 1,2·10²⁴.
Answer:
Option A.
Explanation:
1 mol of anything contains 6.02×10²³ particles.
We know that 1 mol of oxygen gas contains 2 moles of O.
1 mol of oxygen weighs 16 g/mol, the mass for 1 molecule of O.
By the way, the mass for 1 mol of O₂ may be:
Option A → 16 g/mol . 2 mol
32 g
Oyxgen is a dyatomic molecule, that's why we have 2 moles of O.
Another example can be:
1 mol of water (H₂O) contains 2 moles of H and 1 mol of O.
The answer to problem is [He] 2s1. Hope it helps
Taking into account the definition of entropy, the entropy increases (option B).
<h3>What is Entropy</h3>
Entropy can be interpreted as a measure of the random distribution of a system. In other words, the entropy S is a state function that measures the degree of molecular disorder of systems.
In this way, the change in entropy shows the change in molecular order that occurs in a chemical reaction. If the increase in entropy is positive, the products have a higher molecular disorder (higher entropy) than the reactants. On the other hand, when the increase is negative, the products are more ordered.
So, the entropy increases in the reaction if the total number of product molecules are greater than the total number of reactant molecules.
<h3>Entropy change in this case</h3>
In this case, there are 12 moles of gaseous product, and 11 moles of gaseous reactant in the equation. This is, there are more moles in the products than in the reactants.
Therefore, the entropy increases (option B).
Learn more about entropy:
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