Ask question

Ask question

All categories

3 years ago

6

A concrete piling of 50 kg is suspended from a steel wire of diameter 1.0 mm and length 11.2 m. How much will the wire stretch?

modulus for steel is 20 x 10^10 N/m^2.

1 answer:

pentagon [3]3 years ago

8 0

Explanation:

It is given that,

Mass of concrete pilling, m = 50 kg

Diameter of wire, d = 1 mm

Radius of wire, r = 0.0005 m

Length of wire, L = 11.2

Young modulus of steel, $Y=20\times 10^{10}\ N/m^2$

The young modulus of a wire is given by :

$Y=\dfrac{\dfrac{F}{A}}{\dfrac{\Delta L}{L}}$

$Y=\dfrac{F.L}{A\Delta L}$

$\Delta L=\dfrac{F.L}{A.Y}$

$\Delta L=\dfrac{50\ kg\times 9.8\ m/s^2\times 11.2\ m}{\pi (0.0005\ m)^2\times 20\times 10^{10}\ N/m^2}$

$\Delta L=0.034\ m$

So, the wire will stretch 0.034 meters. Hence, this is the required solution.

You might be interested in

A block of mass 500 g is attached to a horizontal spring, whose force constant is 25.0 N/m . The block is undergoing simple harm

lara [203]

Answer:

t = 0.325343 sec

Explanation:

given

mass of block(m) = 500 g

force constant (k) = 25.0 N/m

we know simple harmonic motion equation as

y = A sin (ωt + Φ)

where Φ = $sin^{-1} (-4/6)$

so we get

Φ = - 0.729727656 rad

and we know

$\omega = \sqrt{\frac{k}{m}$

$y = A sin (t\sqrt\frac{k}{m} - 0.729727656)$

now substitute the values we get as

y = 0.06 m

$0.06 = 0.06 sin (t\sqrt(\frac{25}{0.5}) - 0.729727656)$

$(t\frac{25}{0.5} - 0.729727656) = \frac{\pi}{2}$

on solving these equation we get

t = 0.325343 sec

7 0

2 years ago

After travelling 4.0 km, the train reaches its maximum speed. it continues at this constant speed on the next section of the tra

lozanna [386]

Answer:

toward the center of the circular curve

Explanation:

An object will follow a circular path at constant speed if and only if its net acceleration is constant and directed toward the center of the curved path.

__

The result force is directed toward the center of the circle.

_____

<em>Additional comment</em>

If any part of the result force is in the direction of motion, the speed will not be constant. If the center-directed force is not constant, the path will not be circular.

5 0

1 year ago

The vibrations produced by a jackhammer are used to break up pavement. What type of waves did/does the jackhammer produce into t

klio [65]

<span>P waves

P-waves are sometimes called pressure waves, and sometimes they are called longitudinal waves. P-waves are transmitted through the Earth’s interior with a backwards and forwards motion along the line of travel, by alternating compression and dilatation. A jack hammer creates P-waves. They are capable of passing through any type of material they encounter, including the liquid of the Earth’s outer core, although they
will be bent and deflected when they pass across the boundaries separating
layers of different densities.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>

8 0

3 years ago

A 60-kg swimmer suddenly dives horizontally from a 150-kg raft with a speed of 1.5 m/s. The raft is initially at rest. What is t

scZoUnD [109]

I’m almost positive it 60 m/s

7 0

2 years ago

A car initially traveling at 27.2 m/s undergoes a constant negative acceleration of magnitude 1.90 m/s2 after its brakes are app

zubka84 [21]

Answer:

Therefore, the revolutions that each tire makes is:

$\Delta \theta=22\: rev$

Explanation:

We can use the following equation:

$\omega_{f}^{2}=\omega_{i}^{2}-2\alpha \Delta \theta$ (1)

The angular acceleration is:

$a_{tan}=\alpha R$

$\alpha=\frac{1.9}{0.325}$

$\alpha=5.85\: rad/s^{2}$

and the initial angular velocity is:

$\omega_{i}=\frac{v}{R}$

$\omega_{i}=\frac{27.2}{0.325}$

$\omega_{i}=83.69\: rad/s$

Now, using equation (1) we can find the revolutions of the tire.

$0=83.69^{2}-2*25.85 \Delta \theta$

$\Delta \theta=135.47\: rad$

Therefore, the revolutions that each tire makes is:

$\Delta \theta=22\: rev$

I hope it helps you!

6 0

2 years ago