Answer:
the wooden animal will go 0.7068 m above its equilibrium
Explanation:
Given the data in the question;
mass of wooden animal m = 120 g = 0.12 kg
the animal oscillates up and down, T = 0.54 s
older sister pulls the animal 32 cm below its equilibrium position;
x = 32 cm = 0.32 m
g = 9.81 m/s²
We know that
k = mω²
where ω = 2π/T
So, k = m( 2π/T )²
we substitute
k = 0.12( 2π / 0.54 )²
k = 0.12 × (11.6355)²
k = 0.12 × 135.38486
k = 16.25 N/c
so Also,
kx²/2 = mgh
we solve for h
h = kx² / 2mg
we substitute
h = ( 16.25 × (0.32)²) / ( 2 × 0.12 × 9.81 )
h = 1.664 / 2.3544
h = 0.7068 m
Therefore, the wooden animal will go 0.7068 m above its equilibrium
The greek letter λ (lamda) is used to represent the wavelength of the wave.
Answer:
lasing threshold condition is 32.78 cm
Explanation:
given data
uncoated facets R = 0.32
a = 10 cm
length L = 500 um = m
to find out
lasing threshold condition
solution
we know lasing threshold condition formula that is
lasing threshold = a - ln ..........1
put here all value in equation 1 we get
lasing threshold = a - ln
lasing threshold = 10 - ln
lasing threshold = 32.78
so lasing threshold condition is 32.78 cm
Answer:
D
Explanation:
30 m/s is the hypothenuse. The horizontal component will be x. Using trig, you can see that
Answer:
-18
Explanation:
acellus use the formula of magnification and watch your minus sign