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3 years ago

The main difference between the Richter scale and the Mercalli intensity scale is _____.

2 answers:

7 0

C.) -the Richter measures the energy released from an earthquake while the Mercalli measures the effects of an earthquake

Rus_ich [418]3 years ago

3 0

<span>The Richter measures multiple sources of energy being released while the Mercalli measures energy released from the epicenter or focus.</span>

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A remote-controlled car runs on a 9V battery. If a 1.5A current is running through the circuit, what resistance is the car prov

Aleonysh [2.5K]

Ohm's law:

V = I * R, so R = V/I = 9/1.5 = 6 Ohm

4 0

3 years ago

120 J of work was done to lift an object 6 m above

Slav-nsk [51]

Answer:

The last option, 20 N and 2.04 kg

Explanation:

work = (force)(distance)

work = 120 joules

distance: 6 m

rearrange to find force:

120=(6)F

F= 120/6 = 20 Newtons.

Assuming its lifted from Earth's surface, the force of gravity will be 9.81 m/s^2. Let's find mass:

F=mg

m=F/g

m=(20)/(9.81)= 2.038 kg

6 0

2 years ago

An electric flux of 147 N*m^2/C passes through a flat horizontal surface that has an area of 0.824 m^2. The flux is due to a uni

Tresset [83]

Answer:231.16 N/C

Explanation:

Given

Electric Flux $=147 N-m^2/C$

Area(A) $=0.824 m^2$

Given Field point above $31.6 ^{\circ}$

Therefore angle between Area vector Electric Field =90-31.6= $58.4^{\circ}$

We know that Flux is given by

$\phi =\vec{E}\cdot \vec{A}$

$\phi =EAcos\theta$

$147=E\times 0.824\times cos(58.4)$

E=231.16 N/C

4 0

3 years ago

A family communicating using a cell phone at dinner. Using a cell phone is more addicted to technology things than missed opport

tatyana61 [14]

Answer:

The family may be addicted to technology by using their cellphones to communicate is still communicating in a way, but it would be better to use social face- to - face interactions.

Explanation:

4 0

3 years ago

Read 2 more answers

Concept Simulation 20.4 provides background for this problem and gives you the opportunity to verify your answer graphically. Ho

77julia77 [94]

Answer:

The time constant is 1.049.

Explanation:

Given that,

Charge $q{t}= 0.65 q_{0}$

We need to calculate the time constant

Using expression for charging in a RC circuit

$q(t)=q_{0}[1-e^{-(\dfrac{t}{RC})}]$

Where, $\dfrac{t}{RC}$ = time constant

Put the value into the formula

$0.65q_{0}=q_{0}[1-e^{-(\dfrac{t}{RC})}]$

$1-e^{-(\dfrac{t}{RC})}=0.65$

$e^{-(\dfrac{t}{RC})}=0.35$

$-\dfrac{t}{RC}=ln (0.35)$

$-\dfrac{t}{RC}=-1.049$

$\dfrac{t}{RC}=1.049$

Hence, The time constant is 1.049.

6 0

3 years ago