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V125BC [204]
3 years ago
5

Look back at your data and your regression equation. (Sample data is shown to the right, with X= pressure and Y=volume.) click a

ll statements that are true.
Answered.

Chemistry
1 answer:
laiz [17]3 years ago
5 0
<span>Select the block of cells to be included in the scatter plot by clicking and dragging, then from the Insert ribbon under Chart drop down the Scatter or Bubble menu and select Scatter.  A chart will appear on the spreadsheet.
</span><span>
To set up a scatter plot in Excel, enter the pairs of data in two columns with each value of a pair on the same row.  By default, Excel considers the column on the left to contain the horizontal (X) values and the column on the right to contain the vertical (Y) values.

</span><span>If you click on the + sign at the upper right of the chart, a list of checkboxes will appear.  Check Axes, Axis Titles, and Trendline.  Uncheck everything else.  You should edit the Axis Titles to include the name of the factor and any units associated with it.  Double-click on the Axis numbers to bring up the Format Axis dialog, then click on the bar-graph icon to access Axis Options.  Set the bounds and units appropriately and set the tick marks to something sensible.</span><span>

</span>
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How many kilojoules of energy would be required to heat a 225g block of aluminum from 23.0 C to 73.5 C?
gulaghasi [49]

Answer:

\boxed {\boxed {\sf 10.2 \ kJ}}

Explanation:

We are asked to find how many kilojoules of energy would be required to heat a block of aluminum.

We will use the following formula to calculate heat energy.

q=mc \Delta T

The mass (m) of the aluminum block is 225 grams and the specific heat (c) is 0.897 Joules per gram degree Celsius. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature.

  • ΔT = final temperature - inital temperature

The aluminum block was heated from 23.0 °C to 73.5 °C.

  • ΔT= 73.5 °C - 23.0 °C = 50.5 °C

Now we know all three variables and can substitute them into the formula.

  • m= 225 g
  • c= 0.897 J/g° C
  • ΔT= 50.5 °C

q= (225 \ g )(0.897 \ J/g \textdegree C)(50.5 \textdegree C)

Multiply the first two numbers. The units of grams cancel.

q= (225 \ g  * 0.897 \ J/g \textdegree C)(50.5 \textdegree C)

q= (225   * 0.897 \ J / \textdegree C)(50.5 \textdegree C)

q= (201.825\ J / \textdegree C)(50.5 \textdegree C)

Multiply again. This time, the units of degrees Celsius cancel.

q= 201.825 \ J * 50.5

q= 10192.1625 \ J

The answer asks for the energy in kilojoules, so we must convert our answer. Remember that 1 kilojoule contains 1000 joules.

\frac { 1  \ kJ}{ 1000 \ J}

Multiply by the answer we found in Joules.

10192.1625 \ J * \frac{ 1 \ kJ}{ 1000 \ J}

10192.1625  * \frac{ 1 \ kJ}{ 1000 }

\frac {10192. 1625}{1000} \ kJ

10.1921625 \ kJ

The original values of mass, temperature, and specific heat all have 3 significant figures, so our answer must have the same. For the number we found, that is the tneths place. The 9 in the hundredth place tells us to round the 1 up to a 2.

10.2 \ kJ

Approximately <u>10.2 kilojoules</u> of energy would be required.

3 0
2 years ago
During which era did the supercontinent Pangaea break up?
Rudiy27
It broke up in the Mesozoic era.
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2 years ago
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Charles is given two electrical conductors – aluminium and graphite. Help him to select one for making an electric wire. Justify
Iteru [2.4K]

Answer: aluminum I think

Explanation:

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3 years ago
This is the question i need help on
mash [69]
I thank that your answer is C.
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What is the reduction half-reaction for the following unbalanced redox equation?
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First find the oxidation states of the various atoms: 
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<span>Note that N gained electrons, ie, was reduced; Cr was oxidized </span>
<span>Now there is a problem, because B has NH4+ which the problem did not, and is not balanced, showing e- in/out </span>
<span>B.NH4+ → N2 </span>

<span>Which of the following is an oxidation half-reaction? </span>
<span>A.Sn 2+ →Sn 4+ + 2e- </span>
<span>Sn lost electrons so it got oxidized</span>
5 0
3 years ago
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