Short Answer: <span>Solutions of dilute, weak acids - the only kind that you might taste - are sour. Weak, dilute bases are bitter. Solutions of bases are slippery.
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Answer:
Explanation:
3 moles per Liter = 3 molar
Answer:
1.38g/cm 3
Copper-More Dense than 1.38g/cm 3
Answer:
2K3PO4(aq) + 3MgCl2(aq) → Mg3(PO4)2(s) + 6KCl(aq)
Explanation:
K3PO4(aq) + MgCl2(aq)→ Mg3(PO4)2(s) + KCl(aq) (unbalanced)
2K3PO4(aq) + 3MgCl2(aq) → Mg3(PO4)2(s) + 6KCl(aq)
Reactants: Products:
K: 3x2=6 K: 1x6=6
P: 1x2=2 P: 1x2=2
O: 4x2=8 O: 4x2=8
Mg: 1x3=3 Mg: 3x1=3
Cl: 2x3=6 Cl: 1x6=6
Therefore the equation is balanced. Hope this helps.
Answer:
44.8 L
Explanation:
One mole of any gas occupies 22.4 L under standard temperature (0°C = 273 K) and standard pressure (1 atm). Under those same conditions, the volume occupied by 2 moles of methane, assuming ideal behavior is:
2 mol × (22.4 L/ 1 mol) = 44.8 L
2 moles of methane under STP occupy a volume of 44.8 L.