If you have 30 grams of oxygen, how many atoms are present?

Chemistry

1 answer:

umka21 [38]3 years ago

3 0

Answer:

1 × 10²⁴ atoms O

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

30 g O

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of O - 16.00 g/mol

Step 3: Convert

$30 \ g \ O(\frac{1 \ mol \ O}{16.00 \ g \ O} )(\frac{6.022 \cdot 10^{23} \ atoms \ O}{1 \ mol \ O} )$ = 1.12913 × 10²⁴ atoms O

Step 4: Check

We are given 1 sig fig. Follow sig fig rules and round.

1.12913 × 10²⁴ atoms O ≈ 1 × 10²⁴ atoms O

You might be interested in

(c) Draw the structure of any two aminoacids which bears a heterocyclic unit as all or part of the R side chain of the aminoacid

BaLLatris [955]

Answer:

Here I show you tryptophan and tyrosine

Explanation:

of the 21 amino acids, there is five amino acid that have a heterocyclic group as part of the R side chain: Histidine, proline, Phenylalanine, tyrosine, and tryptophan. Each one has a unique nature and the heterocyclic group, mainly in tyrosine, and tryptophan allows to absorb the UV light (280 nm)