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JulijaS [17]
3 years ago
14

How many moles are present in 34 grams of cu(oh)2? *?

Chemistry
1 answer:
lakkis [162]3 years ago
3 0
Question Answer
How many moles are present in 34 grams of Cu(OH)2?
34 grams = 0.35 moles
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A balloon filled with 1.22 L of gas at 286 K is heated until the
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Answer: 670K

Explanation:

Given that,

Original volume of gas V1 = 1.22 L

Original temperature T1 = 286 K

New volume V2 = 2.86 L

New temperature T2 = ?

Since volume and temperature are involved while pressure is constant, apply the formula for Charles law

V1/T1 = V2/T2

1.22 L/286 K = 2.86 L/ T2

Cross multiply

1.22 L x T2 = 286 K x 2.86 L

1.22T2 = 817.96

Divide both sides by 1.22

1.22T2/1.22 = 817.96/1.22

T2 = 670.459 K (Round to the nearest whole number as 670 K)

Thus, the temperature of the gas is 670 Kelvin

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3 years ago
A mole is the amount of a substance that contains as many particles as the number of atoms in 12 grams of what isotope?
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The SI unit for amount<span> of </span>substance<span> is the </span>mole<span>. It has the unit symbol mol. The proportionality constant is the inverse of the Avogadro constant. The </span>mole<span> is defined as the </span>amount<span> of </span>substance that contains<span> an equal </span>number<span> of elementary entities as there are </span>atoms in 12g<span> of the </span>isotope<span> carbon-</span>12<span>.

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Which of the following statements correctly describes the relationship between volume and temperature( moles and pressure of gas
lorasvet [3.4K]

Answer:

pressure of gas are constant describe the relationship between moles and temprature

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8 moles Cl to grams 3
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Answer: I don’t understand what your asking elaborate more

Explanation:

7 0
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20. What volume of 0.350M KMnO4 solution must be diluted to prepare 600. mL of
Dafna1 [17]

Answer:

25.7 mL

Explanation:

Step 1: Given data

  • Initial volume (V₁): ?
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  • Final volume (V₂): 600 mL
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Step 2: Calculate the volume of the initial solution

We have a concentrated solution and we want to prepare a diluted one. We can calculate the initial volume using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.150 M × 600 mL / 0.350 M

V₁ = 25.7 mL

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3 years ago
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